Answer:
x=-1539/445, y=1724/445. (-1539/445, 1724/445).
Step-by-step explanation:
y=9x+35
y=-8/9x+4/5
-------------------
9x+35=-8/9x+4/5
9x-(-8/9x)=4/5-35
9x+8/9x=4/5-175/5
81/9x+8/9x=-171/5
89/9x=-171/5
x=(-171/5)/(89/9)
x=(-171/5)(9/89)
x=-1539/445
y=9(-1539/445)+35
y=1724/445
Answer:
see explanation
Step-by-step explanation:
Given the 2 equations
3x - 5y = - 2 → (1)
2x + y = 3 → (2)
Multiply (2) by 5 will eliminate y when added to (1), that is
10x + 5y = 15 → (3)
Add (1) and (3) term by term
(3x + 10x) + (- 5y + 5y) = (- 2 + 15)
13x = 13 ( divide both sides by 13 )
x = 1
Substitute x = 1 into (2) for corresponding value of y
2 + y = 3 ⇒ y = 3 - 2 = 1
Solution is (1, 1)
Answer:
Step-by-step explanation:
Represent the length of one side of the base be s and the height by h. Then the volume of the box is V = s^2*h; this is to be maximized.
The constraints are as follows: 2s + h = 114 in. Solving for h, we get 114 - 2s = h.
Substituting 114 - 2s for h in the volume formula, we obtain:
V = s^2*(114 - 2s), or V = 114s^2 - 2s^3, or V = 2*(s^2)(57 - s)
This is to be maximized. To accomplish this, find the first derivative of this formula for V, set the result equal to 0 and solve for s:
dV
----- = 2[(s^2)(-1) + (57 - s)(2s)] = 0 = 2s^2(-1) + 114s - 2s^2
ds
Simplifying this, we get dV/ds = -4s^2 + 114s = 0. Then either s = 28.5 or s = 0.
Then the area of the base is 28.5^2 in^2 and the height is 114 - 2(28.5) = 57 in
and the volume is V = s^2(h) = 46,298.25 in^3
Answer:
I think the answer is A
Sorry if i am wrong
Step-by-step explanation:
Answer:
The radius is 1
Step-by-step explanation: