Answer:
Given:
......[1]
To prove : x =78
Subtraction property states that you subtract the same number to both sides of an equation.
Subtract 2 from both sides of an equation [1];
Simplify:
......[2]
Multiplication property states that you multiply the same number to both sides of an equation.
Multiply 6 to both sides of an equation [2];
![\frac{x}{6} \times 6 = 13 \times 6](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7B6%7D%20%5Ctimes%206%20%3D%2013%20%5Ctimes%206)
Simplify:
proved!
Statement Reason
1.
Given
2.
Subtraction property of equality
3.
Multiplication property of equality
1 lb / 0.45 = 2.22
so approximately 2.22 kilograms per pound
divide price per pound by kilometers per pound
1.44 / 2.22 = 0.648
round to 0.65, so it costs $0.65 per kilogram
Answer: 1/3
Step-by-step explanation:
if you make a fraction 5/15 pizzas and simplify it is is equal to 1/3.
Original position:
A-(-8,-4)
B-(-6,3)
C-(-3,7)
D-(-2,-2)
Translation:
A'-(-4,-4)
B'-(-2,3)
C'-(1,7)
D'-(2,-2)
Vertex C will be in quadrant 1 (+,+) after being translated 4 unites to the right.
Answer:
0.000064 = 0.0064% probability that the box will contain less than the advertised weight of 466 g.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
N(489,6)
This means that ![\mu = 489, \sigma = 6](https://tex.z-dn.net/?f=%5Cmu%20%3D%20489%2C%20%5Csigma%20%3D%206)
What is the probability that the box will contain less than the advertised weight of 466 g?
This is the p-value of Z when X = 466. So
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{466 - 489}{6}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B466%20-%20489%7D%7B6%7D)
![Z = -3.83](https://tex.z-dn.net/?f=Z%20%3D%20-3.83)
has a p-value of 0.000064
0.000064 = 0.0064% probability that the box will contain less than the advertised weight of 466 g.