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marta [7]
3 years ago
11

What integer divided by -5 equals -6? -30 24 -24 30

Mathematics
2 answers:
lubasha [3.4K]3 years ago
8 0

Answer:

30

Step-by-step explanation: ty for reminding me of the integer rules dperez1308

Minchanka [31]3 years ago
4 0

Answer:

30

Step-by-step explanation:

30/-5=-6

due to integer rules the number would be negative

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Anne’s family stops in a store that is having a 20% sale. That means the customer pays 80% of the regular price. How much would
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Which table most accurately organizes the data from the graph?
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Answer

It's B

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It organizes the years from 1-6 and keeps the money consistent with the years

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2 years ago
Birth weights of a sample of newborn babies
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Answer:  Birth-weight (Kilogram) Number (n) Percentage (%)

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5 0
3 years ago
A simple random sample of 81 8th graders at a large suburban middle school indicated that 87% of them are involved with some typ
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The 90% confidence interval that estimates the proportion of 8th graders that are involved in an after-school activity is (0.80853,0.93147).

The confidence interval for a population proportion for a given sample is given by the formula:

(p-Z\sqrt{\frac{p(1-p}{n} } , p+Z\sqrt{\frac{p(1-p}{n} }),

where p is the population proportion, Z is the Z-score value for the confidence interval, and n is the sample size.

In the question, we are given a random sample of 81 8th graders at a large suburban middle school. This implies that the sample size, n = 81. Also, we are told that they indicated 87% of them were involved with some type of after-school activity. This implies that the population proportion, p = 87% = 0.87.

We are asked to find the 90% confidence interval that estimates the proportion of them that are involved in an after-school activity.

Z-score (Z) corresponding to a 90% confidence interval is 1.645.

Thus, we can find the confidence interval as follows:

(0.87 - 1.645√{(0.87(1 - 0.87))/81},0.87 + 1.645√{(0.87(1 - 0.87))/81})

= (0.87 - 0.061469,0.87 + 0.061469)

= (0.80853,0.93147).

Thus, the 90% confidence interval that estimates the proportion of 8th graders that are involved in an after-school activity is (0.80853,0.93147).

Learn more about confidence intervals of population proportions at

brainly.com/question/13950323

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