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GuDViN [60]
2 years ago
13

A study of a population of 3600 dogs found that 6 out of every 90 dogs have brown fur. Based on the results of this study, how m

any dogs in the population DO NOT have brown fur?
Mathematics
1 answer:
nika2105 [10]2 years ago
4 0
3600/90= 40 x 6 =240
3600 - 240 = 3360
3360 dogs in the population DO NOT have brown fur.
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Given that f(x)=2x/3 evaluate f^-1(6)
abruzzese [7]

Answer:

9

Step-by-step explanation:

we know by definition that

f^{-1}(f(x))=x\\\\f^{-1}(\frac{2x}{3})=x\\\\f^{-1}(x)=ax\\\\f^{-1}(\frac{2x}{3})=a(\frac{2x}{3})=x\\\\f^{-1}(x)=\frac{3x}{2}

so now we evaluate

f^{-1}(6)=\frac{3*6}{2}\\\\=3*3\\\\f^{-1}(6)=9

and if we want to do an extra step

f^{-1}(f(6))=6\\\\f^{-1}(\frac{2*6}{3})=f^{-1}(4)=\frac{3*4}{2}=6

which works.

4 0
2 years ago
Pls help <br><br> Thank you ❤️
nikdorinn [45]

Answer:

the difference is 78

the avg drop is 3 degrees per kilometer

Step-by-step explanation:

Hope this helps

4 0
3 years ago
Learn with an example
Marta_Voda [28]

Answer:

y = 9x + (-7) should be the answer

6 0
3 years ago
Twenty students are members of the school debate team. Five
harkovskaia [24]

Answer:

75%

Step-by-step explanation:

\frac{15}{20} as a percent = 75%, or 0.75 in decimal form.

8 0
2 years ago
At a raffle, 1500 tickets are sold at $2 each. There are four prizes given for $500, $250, $150, and $75. You buy one ticket. Us
wolverine [178]

Answer:

<u>The expected value of every ticket is a loss of $ 1.35</u>

Step-by-step explanation:

1. Let's review the information provided to us to answer the question correctly:

Number of tickets sold at the raffle = 1,500

Price of each ticket = $ 2

Total prizes = 1 * $ 500 + 1 * $ 250 + 1 * $ 150 + 1 * $ 75

2. Use a probability distribution table to calculate the expected value of your gain. Your expected value is_____ ?

Let's answer the question using a probability distribution for the gains, this way:

  • Probability of 1st prize of $ 498 (500 - ticket) = 1/1,500
  • Probability of 2nd prize of $ 248 (250 - ticket) = 1/1,500
  • Probability of 3rd prize of $ 148 (150 - ticket) = 1/1,500
  • Probability of 4th prize of $ 73 (75 - ticket) = 1/1,500
  • Probability of losing $ 2 (ticket) = 1,496/1,500

Now, we calculate the mean for all the tickets (winners and non-winners), this way:

Expected value = [(1,496 * -2) + (1 * 498) + (1 * 248) + ( 1 * 148) + ( 1 * 73)]/1,500

Expected value = [- 2,992 +498 + 248 + 148 + 73)/1,500

Expected value = -2,025/1,500 = - 1,35

<u>The expected value of every ticket is a loss of $ 1.35</u>

8 0
3 years ago
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