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ozzi
3 years ago
13

Which values of a and b make the equation true?

Mathematics
2 answers:
xxMikexx [17]3 years ago
7 0

Answer:

a = 3 & b = 3

Step-by-step explanation:

\small \sf \: \frac{ ( 4 xy )⁴ }{4xy  }= 4x {}^{a} y {}^{b}  \\

2⁴ x⁴ y ⁴ / 4 xy

simplify

16 x⁴ y⁴ / 4 xy

\small \sf  \frac{a {}^{b} }{a {}^{c} } \:  = a {}^{b - c}

16 / 4 × x⁴ - x × y⁴ - y

4 x³ y³

Therefore , a = 3 and b = 3

zimovet [89]3 years ago
5 0

Answer:

a=3

b=3

Step-by-step explanation:

(2xy)^4

----------------

4xy

Expand the numerator

2^4 x^4 y^4

---------------------

4xy

Simplify

16 x^4 y^4

---------------------

4xy

We know that a^b / a^c = a^(b-c)

16/4 * x^(4-1)  y^(4-1)

4 x^3 y^3

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What is the equation of the line that passes through the point (5,-2) and (2,-5)
Inga [223]

Answer:

(4, 10)

Step-by-step explanation: you go 4 over from 2 and you get -2. if you go over 10 you get -5

7 0
3 years ago
The tables represent the functions f(x) and g(x).
dolphi86 [110]

A function assigns the values. The correct option is C, x=-6.

<h3>What is a Function?</h3>

A function assigns the value of each element of one set to the other specific element of another set.

A.) When the value of x is -12,

f(-12) = 2/3(-12) + 7 = -1

g(-12) = 2(-12) + 15 = -9

B.) When the value of x is -9,

f(-9) = 2/3(-9) + 7 = 1

g(-9) = 2(-9) + 15 = -3

C.) When the value of x is -6,

f(-6) = 2/3(-6) + 7 = 3

g(-6) = 2(-6) + 15 = 3

D.) When the value of x is -3,

f(-9) = 2/3(-3) + 7 = 5

g(-9) = 2(-2) + 15 = 11

Hence, the correct option is C, x=-6.

Learn more about Function:

brainly.com/question/5245372

#SPJ1

4 0
2 years ago
A bag contains the following marbles: 4 black marbles, 14 blue marbles, 8 brown marbles, and 20 green marbles. What is the ratio
Diano4ka-milaya [45]

Answer:

14/8 or 14:8

Step-by-step explanation:

blue:brown=14:8

3 0
3 years ago
Does anyone know how to do this? Im so confused.
Dafna11 [192]
<h3>Answer:  PC = 5</h3>

================================================

Work Shown:

AB+BC+CD = AD .... segment addition postulate

BC+BC+CD = AD ... replace AB with BC (since AB = BC)

BC+BC+BC = AD ... replace CD with BC (since BC = BC)

3*BC = AD .... combine like terms

3*BC = 12 .... replace AD with 12

BC = 12/3 .... divide both sides by 3

BC = 4

For right triangle PBC, the legs are BP = 3 and BC = 4. We can use the Pythagorean Theorem to find that the hypotenuse is PC = 5

The steps are shown below

(BP)^2+(BC)^2 = (PC)^2

3^2+4^2 = (PC)^2

9+16 = (PC)^2

25 = (PC)^2

(PC)^2 = 25

PC = sqrt(25)

PC = 5

The other parts of the diagram seem to be thrown in as a distraction.

7 0
3 years ago
If 2(a^2+b^2)=(a+b)^2 then, <br> &gt;a+b=0,<br> &gt;ab=0,<br> &gt;a=b,<br> &gt;2a=b
Tasya [4]

Answer:

2·(a^2 + b^2) = (a + b)^2

2·a^2 + 2·b^2 = a^2 + 2·a·b + b^2

a^2 + b^2 = 2·a·b

a^2 - 2·a·b + b^2  = 0

(a - b)^2 = 0

a = b


7 0
3 years ago
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