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irga5000 [103]
3 years ago
8

CAN SOMEONE PLEASE HELP ME WITH THESE

Mathematics
1 answer:
alexgriva [62]3 years ago
7 0
It’s c I think hope this helped
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A car originally worth $32,000 is now worth only $14,000. By how much did the car depreciate?
yuradex [85]

Answer:

18,000 because 32+14=18

3 0
2 years ago
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The amount of saturated fat in a daily serving of a particular brand of breakfast cereal is normally distributed with mean 25 g
Soloha48 [4]

Answer:

a) \bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And replacing we got:

\bar X \sim N(\mu=25, \frac{4}{\sqrt{30}}= 0.730)

b) z =\frac{27-25}{\frac{4}{\sqrt{30}}}= 2.739

And using the normal standard distribution table and the complement rule we got:

P(z>2.739) =1- P(z

Step-by-step explanation:

From the info given if we define the random variable X as "amount of saturated fat in a daily serving of a particular brand of breakfast cereal " we know that the distribution of X is given by:

X \sim N(\mu =25, \sigma =4)

Part a

For this case the sample size would be n =30 and then the distribution for the sample mean would be given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And replacing we got:

\bar X \sim N(\mu=25, \frac{4}{\sqrt{30}}= 0.730)

Part b

We want to find this probability:

P(\bar X >27)

And we can use the z score formula given by:

z=\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And replacing we got:

z =\frac{27-25}{\frac{4}{\sqrt{30}}}= 2.739

And using the normal standard distribution table and the complement rule we got:

P(z>2.739) =1- P(z

3 0
3 years ago
BRANLIEST and 35 points. Design, explain, work out, and explain the answer for an equation using the formula to calculate force
NISA [10]

Answer:

What is the smallest angle of rotational symmetry for the regular octagon?

°

Step-by-step explanation:

4 0
2 years ago
The​ "fear of negative​ evaluation" (FNE) scores for 11 random female students known to have an eating disorder (1) and 14 rando
SOVA2 [1]

Answer:

a. The 95% confidence interval for the difference in mean is C.I. = -3.6 < μ₂ - μ₁ < 4.96

B. We are 95% confident that the difference in mean FNE scores for bulimic and normal students is inside the confidence interval

c.  The assumptions made are;

The variance of the two distributions are equal

Step-by-step explanation:

The given parameters are;

The mean for the 11 students with an eating disorder, \overline x_1 = 13.82

The standard deviation for the 11 students with an eating disorder, s₁ = 4.92

The mean for the 14 students who do not have an eating disorder, \overline x_2 = 13.14

The standard deviation for the 14 students with an eating disorder, s₂ = 5.29

a. The 95% confidence interval for the difference in mean is given as follows;

\left (\bar{x}_{1}- \bar{x}_{2}  \right )\pm t_{\alpha /2}\sqrt{ \hat \sigma^2 \times\left( \dfrac{1}{n_{1}}+\dfrac{1}{n_{2}} \right)}

The pooled standard deviation, is therefore;

\hat{\sigma} =\sqrt{\dfrac{\left ( n_{1}-1 \right )\cdot s_{1}^{2} +\left ( n_{2}-1 \right )\cdot s_{2}^{2}}{n_{1}+n_{2}-2}}

Therefore;

\hat{\sigma} =\sqrt{\dfrac{\left ( 11-1 \right )\cdot4.92^{2} +\left ( 14-1 \right )\cdot 5.29^{2}}{11+14-2}} \approx 5.13241

Where at degrees of freedom, df = n₁ + n₂ - 2 = 25 - 2 = 23 the critical-t = 2.07

\left (13.82- 13.14  \right )\pm 2.07 \times\sqrt{5.13241^2 *(\dfrac{1}/{11}+\dfrac{1}{14}\right)}

C.I. = \left (13.82- 13.14  \right )\pm 2.07 \times\sqrt{5.13241^2 \times\left(\dfrac{1}{11}+\dfrac{1}{14}\right)}

Therefore, we get;

C.I. = 0.68\pm 4.28

C.I. = -3.6 < μ₂ - μ₁ < 4.96

b. Therefore, given that the confidence interval extends from positive to negative, therefore, there is a possibility that there is no difference between the mean FNE scores for bulimic and normal students

B. We are 95% confident that the difference in mean FNE scores for bulimic and normal students is inside the confidence interval

c.  The assumptions made are;

The variance of the two distributions are equal

6 0
3 years ago
BRAINLEST IF CORRECT
DedPeter [7]

Answer:

422.39

Step-by-step explanation:

A = \pi r^2\\A = 144\pi \\\\144\pi -30 = 422.39

use a calculator for the above and round

6 0
3 years ago
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