2.A
3.C
Hope this helped!!!
In this item, it is unfortunate that a figure, drawing, or illustration is not given. To be able to answer this, it is assumed that these segments are collinear. Points L, M, and N are collinear, and that L lies between MN.
The length of the whole segment MN is the sum of the length of the subsegments, LN and LM. This can be mathematically expressed,
LN + LM = MN
We are given with the lengths of the smalller segments and substituting the known values,
MN = 54 + 31
MN = 85
<em>ANSWER: MN = 85</em>
200in^2
The face is made up of 2 squares which have side lengths of 10, 10 times 10 equals 100 and there’s 2 of them which makes 100+100=200in^2
Answer:
y-intercept = a +y^2/12 term in it.
Then for y=6, you have
.. 6^2/12 -x^2/b = 1
.. 2 = x^2/b
.. b = x^2/2
If your point is (2√3, 6), then this is
.. b = (2√3)^2/2 = 12/2 = 6
Then the hyperbola's equation is
.. y^2/12 -x^2/6 = 1 . . . . . . . . selection D
Step-by-step explanation:
