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Lesechka [4]
3 years ago
15

How many can 2 go into 600

Mathematics
2 answers:
saul85 [17]3 years ago
7 0
300 it can go into are you 3 years old
algol [13]3 years ago
6 0
300 is the answer because it’s 600/2
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makkiz [27]

Answer:

C. y=1/2x+4

Step-by-step explanation:

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Concept of Function - Quiz - Level H
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Which is the simplified form of the expression ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript nega
AlekseyPX

Answer:

The option "StartFraction 1 Over 3 Superscript 8" is correct

That is \frac{1}{3^8} is correct answer

Therefore [(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}

Step-by-step explanation:

Given expression is ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript negative 3 Baseline times ((2 Superscript negative 3 Baseline) (3 squared)) squared

The given expression can be written as

[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2

To find the simplified form of the given expression :

[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2

=(2^{-2})^{-3}(3^4)^{-3}\times (2^{-3})^2(3^2)^2 ( using the property (ab)^m=a^m.b^m )

=(2^6)(3^{-12})\times (2^{-6})(3^4) ( using the property (a^m)^n=a^{mn}

=(2^6)(2^{-6})(3^{-12})(3^4) ( combining the like powers )

=2^{6-6}3^{-12+4} ( using the property a^m.a^n=a^{m+n} )

=2^03^{-8}

=\frac{1}{3^8} ( using the property a^{-m}=\frac{1}{a^m} )

Therefore [(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}

Therefore option "StartFraction 1 Over 3 Superscript 8" is correct

That is \frac{1}{3^8} is correct answer

6 0
3 years ago
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Arada [10]

Answer:

x<16

Step-by-step explanation:

number<em> n </em>

eight less than four times a number ... 4 x <em>n</em> - 8

is less than 56 ... < 56

4 x <em>n</em> - 8 < 56

4 x <em>n</em> < 56 + 8

4 x<em> n</em> < 64/4

<em> n</em> < 64 / 4

<em>n</em> < 16

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2 years ago
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Plz help geometry question is below, asap
inessss [21]

I would say the answer is b. It sounds like the best choice

hope i helped!

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