The area of the semicircle is A = 1187.9 cm².
<h3>What is the area of a circle?</h3>
The area of a circle with a radius of r is A = πr².
Given that, the diameter of the semicircle is 55 cm.
The radius of the semicircle is,
r = 55/2
The area of a semicircle is given by,
A = (1/2)πr²
Substitute the values,
A = (1/2)π(55/2)²
A = 1187.9
Hence, the area of the semicircle is A = 1187.9 cm².
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Side 1: 17 Cm.
Side 2: 7 Cm.
Side 3: 14 Cm.
Hope This Helped.
That is the combination of 10 over 3, which is calculated as the quotient of factorials:
n!/k!(n-k)!
where n = 10 and k = 3:
= 10!/3!(10 - 3)!
= 10!/3!*7!
= (10*9*8)/(3*2*1)
= 720/6
= 120
therefore there a re 120 possible different groups
Step-by-step explanation:
( y = 4x/5 + 2)
m1.m2 = -1
4/5.m2 = -1
m2 = -5/4
formula = y - y1 = m2 ( x - x1)
y - 3 = -5/4 ( x - 6)
y -3 = -5x /4 + 30/4
y = -5x /4 + 21/2
We are given:
the center of the rink at the origin.
A skating path (Susan): y = 6x - x^2 - 5
Starting point of Luke = (10, -21)
Path (Luke) = quadratic eq'n with vertex at (8, -9)
Radius = 35 meters
The solution that best interprets the path of the skaters is to substitute Luke's starting point to Susan's path or set-up a quadratic equation with vertex of (8,-9) and then equate to Susan's path to solve for their intersection.