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laila [671]
3 years ago
13

Harry and Sunil each have the same amount of money.

Mathematics
2 answers:
JulsSmile [24]3 years ago
5 0

Answer:

The answer is 2•5

Step-by-step explanation:

Hope it helps

rosijanka [135]3 years ago
5 0

Answer:

2.5

Step-by-step explanation:

i dunno man its intuition ig

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Ellle bought 6 pineapples for $12.95. Estlm<br> the cost of each pineapple to the nearest cent?
Zarrin [17]

Answer:

$2.16

Step-by-step explanation:

divide $12.95 by 6

12.95/6=2.15833333333

round to the nearest cent : $2.16

4 0
3 years ago
-3&gt;-5+m/2 solve for the varible "m"
Ira Lisetskai [31]

For this case we must solve the expression given for the variable "m":

-3> -5+ \frac {m} {2}

We add 5 to both sides of the inequality:

5-3> \frac {m} {2}\\2> \frac {m} {2}

Multiplying by 2 to both of the inequality:

2 * 2> m\\4> m

So, finally we have:

m

The solution is given by all values of m less than 4.

Answer:

m

6 0
4 years ago
5 ft
Rom4ik [11]

Answer:

Assuming this is a rectangular prism the surface area would be 324ft^2.

Step-by-step explanation:

Surface Area = 2(lw + lh + wh).

3 0
3 years ago
Read 2 more answers
Two chemical companies can supply a raw material. The concentration of a particular element in this material is important. The m
svp [43]

Answer:

As the calculated F lies in the acceptance region therefore we conclude that there is not sufficient evidence to support the claim that the variability in concentration may differ for the two companies. Hence Ha is rejected and H0 is accepted.

Step-by-step explanation:

As we suspect the variability of concentration F - test is applied.

n1=10    s1=4.7

n2=16      s2=5.8

And α = 0.05.

The null and alternate hypothesis are

H0: σ₁²=σ₂²       Ha:  σ₁²≠σ₂²

The null hypothesis is  the variability in concentration does not  differ for the two companies.

against the claim

the variability in concentration may differ for the two companies

The critical region F∝(υ1,υ2) = F(0.025)9,15= 3.12

and 1/F∝(υ1,υ2) = 1/3.77= 0.26533

where υ1= n1-1= 10-1= 9 and υ2= n2-1= 16-1= 15

Test Statistic

F = s₁²/s₂²

F= 4.7²/5.8²=0.6566

Conclusion :

As the calculated F lies in the acceptance region therefore we conclude that there is not sufficient evidence to support the claim that the variability in concentration may differ for the two companies. Hence Ha is rejected and H0 is accepted.

3 0
3 years ago
Five years ago, one share stock was worth %28.00. Today,
gavmur [86]
I believe the answer would be 62.00.
3 0
3 years ago
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