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Masja [62]
3 years ago
6

The scatter plot below shows the ages and heights of a baseball team. Each dot represents one player. What is the total

Mathematics
2 answers:
Jobisdone [24]3 years ago
8 0

Answer:

its 2 because it says how many are 12 years old and are taller than 60

vlada-n [284]3 years ago
7 0

Answer:

D

Step-by-step explanation:

if each dot is one person then there are only 2 people that are 12 and that are more than 60in tall

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(-4-3)(1-(3+5))x5= <br><br><br> how do you solve that problem ?
zavuch27 [327]
(-4 - 3)(1 - (3 + 5)) × 5
(-7)(-1 - 2) × 5
(-7)(-3) × 5
21 × 5
105
7 0
3 years ago
–2x + 2y = -4<br> 3х + Зу = -18
rodikova [14]

Answer:

(-2, -4)

Step-by-step explanation:

–2x + 2y = -4

3х + Зу = -18

Divide the first equation by 2

–2x/2 + 2y/2 = -4/2

-x +y = -2

Divide the second equation by 3

3х/3 + Зу/3 = -18/3

x + y = -6

Add these equation together

-x +y = -2

x + y = -6

-------------------

0x + 2y = -8

2y = -8

Divide each side by 2

2y/2 = -8/2

y = -4

Now we need x

x+y = -6

x-4 = -6

Add 4 to each side

x-4+4 = -6+4

x = -2

3 0
3 years ago
The table shows the concentration of a reactant in the reaction mixture over a period of time.
saveliy_v [14]
<h3>Option C</h3><h3>The average rate of the reaction over the entire course of the reaction is: 2.0 \times 10^{-3}</h3>

<em><u>Solution:</u></em>

Average rate is the ratio of concentration change to the time taken for the change

Average\ rate = \frac{ \triangle c }{\triangle t }

The concentration of the reactants changes 1.8 M to 0.6 M

here, the time interval given is 0 to 580 sec

Therefore,

Average\ rate = \frac{1.8-0.6}{580} \\\\Average\ rate = \frac{1.2}{580} \\\\Average\ rate \approx 2.0 \times 10^{-3}

Thus option C is correct

5 0
3 years ago
Describe the location of the point having the following coordinates.
denis23 [38]

we know that

If the point has an nonzero abscissa (x ​​coordinate) then it can be located in any of the four quadrants

If the point has an negative ordinate (y ​​coordinate) then it can be located in Quadrant III or Quadrant IV

therefore

the answer is the option

Quadrant III or Quadrant IV

7 0
3 years ago
The height after t seconds of an object projected upward with an initial velocity of 48 feet per second from a 210-foot tower ca
svetlana [45]

Given:

The height h of an object after t seconds is

h=-16t^2+48t+210

The height of a neighboring 50-foot tall building is modeled by the equation h=50.

The time (t) when the object will be at the same height as the building is found to be t = –2 and t = 5.

To find:

The statement which describes the validity of these solutions.

Solution:

We have,

h=-16t^2+48t+210

Here, t is the time in seconds.

For t=-2,

h=-16(2)^2+48(-2)+210

h=-64-96+210

h=50

For t=5,

h=-16(5)^2+48(5)+210

h=-400+240+210

h=50

So, the value of h is 50 at t=-2 and t=5.

We know that time is always positive so it cannot be negative value. It means t=-2 is not possible.

The solution t = 5 is the only valid solution to this system since time cannot be negative.

Therefore, the correct option is C.

6 0
3 years ago
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