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2 years ago

PLS HELP ILL GIVE BRAINLY AND 30 PTS

Mathematics

2 answers:

kvv77 [185]2 years ago

8 0

Answer:

C. These lines are perpendicular

Step-by-step explanation:

frosja888 [35]2 years ago

5 0

Answer:

C. the lines are perpendicular

Step-by-step explanation:

you can tell right away they're perpendicular because the slope gets flipped and changed the sign for in the second equation

2/3 going to -3/2 or vice versa means they are perpendicular

if they had the same slope they would have been parallel

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a group raised $276 for its favorite charity. this is 23% of the amount it hopes to raise. how much money does the group want to

OverLord2011 [107]

Answer: The group wants to raise $1,200.

Step-by-step explanation:

We can use a proportion to solve.

part/whole = percent/100

If we insert the values:

276/x = 23/100

We can cross multiply.

276 x 100 = 27,600

27,600 / 23 = 1,200

$1,200 is the answer.

6 0

2 years ago

Anybody who is good with word problems and (who has done these before) plz help thx!!! :DD

vovikov84 [41]

1. $\frac{x}{15} = 3$

2. 8x = 216

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2 years ago

Read 2 more answers

Which shows the equation y – x = 3 written in slope-intercept form? Question 1 options: y – x – 3 = 0 y – 2 = x + 3 y = 3x y = x

Kazeer [188]

Y=x+3
you need to add the x to the opposite side to get y by itself

4 0

3 years ago

Which equation represents a quadratic function?

Elena-2011 [213]

Quadratic is where the degree of x is 2
I would think 3 is the one that might have been written as y=x² which would be correct

8 0

2 years ago

Haya la integral de xarcsenx/((1-x^2)^1/2). Utiliza la sustitución de t= arcsenx

ikadub [295]

Answer:

<em>Explicación más abajo</em>

Step-by-step explanation:

Integración Indefinida

La integral

$I=\int \dfrac{x .arcsen\left(x\right)}{\sqrt{1-x^2}}$

Se resuelve con el cambio de variables:

t=arcsen(x)

Una vez hechos los cambios, la integral se resuelve en función de t:

$I=sen(t)-t.cos(t)+C$

Hay que devolver los cambios para mostrarla en función de x.

El cambio de variables también se puede escribir:

x=sen(t)

Recordando que

$cos(t)=\sqrt{1-sen^2(t)}$

Entonces:

$cos(t)=\sqrt{1-x^2}$

Devolviendo los cambios:

$I=sen(t)-t.cos(t)+C=x-arcsen(x)\sqrt{1-x^2}+C$

Es la respuesta correcta

7 0

2 years ago