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2 years ago

PLS HELP ILL GIVE BRAINLY AND 30 PTS

Mathematics

2 answers:

kvv77 [185]2 years ago

8 0

Answer:

C. These lines are perpendicular

Step-by-step explanation:

frosja888 [35]2 years ago

5 0

Answer:

C. the lines are perpendicular

Step-by-step explanation:

you can tell right away they're perpendicular because the slope gets flipped and changed the sign for in the second equation

2/3 going to -3/2 or vice versa means they are perpendicular

if they had the same slope they would have been parallel

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(x-4)*(x-9)=0 what is x

Strike441 [17]

Answer:

x either equals to 4 of 9 so you can write it like x=4, 9

Step-by-step explanation:

Start by simplifying each sides of the equation.

x^2-13x+36=0

Then factor the left side of the equation.

(x-4)(x-9)=0

Set factors equal to 0

x-4=0 or x-9=0

x=4 or x=9

4 0

2 years ago

Read 2 more answers

12.21 is 3.7 times the number p.

ASHA 777 [7]

P3.7 = 12.21 (p × 3.7 = 12.21)

p÷3.7 = 12.21÷3.7 (p÷3.7 cancels out p×3.7 and leaves you left with the equation p = 12.21÷3.7)

p=3.3

4 0

2 years ago

The data given below contain the state cigarette taxâ€‹ (in $) for all 20 regions of a country.

g100num [7]

Answer:

(a) $\bar x= 1.583$ -- Population Mean

(b) $s = 1.032$ --- Population standard deviation

Step-by-step explanation:

Given:

Cigarette tax for 20 regions

Solving (a): The population mean

This is calculated as:

$\bar x = \frac{\sum x}{n}$

$\sum x = 1.36 + 1.70 + 2.50 + 0.45 + 1.18 + 0.64 + 3.46 + 0.57 + 2.00 + 0.80 + 1.60 +0.98 + 0.36 + 2.24 + 4.35 + 0.62 + 2.70 + 1.78 + 1.53 + 0.84$

$\sum x = 31.66$

$n = 20$

So, we have:

$\bar x= \frac{31.66}{20}$

$\bar x= 1.583$

Solving (b): The population standard deviation

This is calculated as:

$s = \sqrt{\frac{\sum( x - \bar x)^2}{n}$

$\sum (x -\bar x)^2 = (1.36 - 1.583)^2 + (1.70 - 1.583)^2+ (2.50 - 1.583)^2+ (0.45 - 1.583)^2+ (1.18 - 1.583)^2+ (0.64 - 1.583)^2+ (3.46 - 1.583)^2+ (0.57 - 1.583)^2+ (2.00 - 1.583)^2+ (0.80 - 1.583)^2+ (1.60 - 1.583)^2+(0.98 - 1.583)^2+ (0.36 - 1.583)^2+ (2.24 - 1.583)^2+ (4.35 - 1.583)^2+ (0.62 - 1.583)^2+ (2.70 - 1.583)^2+ (1.78 - 1.583)^2+ (1.53 - 1.583)^2+ (0.84- 1.583)^2$