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Brut [27]
3 years ago
12

Solve the equation (128)^x=(1/2)^2x-3​

Mathematics
1 answer:
Sedbober [7]3 years ago
4 0

Answer:

0.3333333333333

Step-by-step explanation:

x= 1/3≈0.333333333

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Você tem $ 20 para gastar com o táxi. A corrida custa $5 mais $2,50d 2,50 por quilômetro.
Aloiza [94]

Answer:

$5 + 2.50k ≤ $20

6 kilometers

Step-by-step explanation:

Puedes viajar con $15 porque gastaste 5 en la tarifa base. 15 dividido por 2,5 es 6, por lo que puedes viajar 6 kilómetros con $20.

5 0
2 years ago
The perimeter of an equilateral triangle is 63 inches. If the length of each side is (4x-3), find the value of x.
balu736 [363]
Equilateral triangle have the same side lengths. Perimeter = sum of all sides
(4x - 3) + (4x - 3) + (4x - 3) = 63
Remove parentheses
4x - 3 + 4x - 3 + 4x - 3 = 63
Combine like terms
12x - 9 = 63
12x = 72, x = 6

Solution: x = 6
4 0
3 years ago
What is the central idea of Langston Hughes’s poem "Mother to Son"?
MariettaO [177]

Answer:

B

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
(1 point) consider the function f(t)=⎧⎩⎨⎪⎪⎪⎪0,−5,−6,6,t<00≤t<11≤t<7t≥7;f(t)={0,t<0−5,0≤t<1−6,1≤t<76,t≥7; 1. wr
sergij07 [2.7K]
f(t)=\begin{cases}0&\text{for }t

Recall that

u(t)=\begin{cases}0&\text{for }t

Take it one piece at a time. For t\ge0, we can scale u(t) by -5:

-5u(t)=\begin{cases}0&\text{for }t

If we shift the argument by 1 and scale by -5, we have

-5u(t-1)=\begin{cases}0&\text{for }t

so if we subtract this from -5u(t), we'll end up with

-5u(t)+5u(t-1)=\begin{cases}0&\text{for }t

For the next piece, we can add another scaled and shifted step like

-6u(t-1)+6u(t-7)=\begin{cases}0&\text{for }t

so that

-5u(t)+5u(t-1)-6u(t-1)+6u(t-7)=\begin{cases}0&\text{for }t

For the last piece, we add one more term:

6u(t-7)=\begin{cases}0&\text{for }t

and so putting everything together, we get f(t):

f(t)\equiv-5u(t)+5u(t-1)-6u(t-1)+6u(t-7)+6u(t-7)
f(t)\equiv-5u(t)-u(t-1)+12u(t-7)
5 0
3 years ago
Ian picked up six teen red cars and 12 black cars from the floor of his room he put the same number of each color cars into two
Ad libitum [116K]
16 red cars and 12 black cars. He put half of each colour in each box. Therefore he would put 8 red and 6 black in each box. 8 red + 6 black is 14. Therefore he would have 14 cars in each box. 

14. 
5 0
3 years ago
Read 2 more answers
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