Answer:
p+q = 10...... 1
0.05p+0.10q = 0.85 ..... 2
Step-by-step explanation:
The question is incomplete. Here is the complete question.
A student has 10 coins in her pocket that have a value of $0.85. The coins are either nickels or dimes. If each nickel costs $0.05 and each dime costs $0.10. Which system of linear equations represents this scenario?
Let the number of nickel in the pocket of the student be p
Let the number of dime in the pocket of the student be q
If there are 10 coins in her pocket, then the total coins in her pocket will be represented by the equation;
p+q = 10...... 1
If each nickel costs $0.05, p nickels will cost $0.05×p = $0.05p
If each dime costs $0.10, q nickel will costs $0.10×q = $0.10q
Total amount will be $0.05p+$0.10q
Now if the total coins in her pocket has a value of $0.85, then the we will equate $0.05p+$0.10q to $0.85 to give our second linear equation as:
$0.05p+$0.10q = $0.85 ....... 2
Therefore, the system of linear equations represents this scenario are:
p+q = 10...... 1
0.05p+0.10q = 0.85 ..... 2
