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irina [24]
3 years ago
6

Please help please please help

Mathematics
1 answer:
aleksklad [387]3 years ago
3 0

Answer:

Step-by-step explanation:

<u><em>   Number    </em></u><em>         </em><u><em>   Estimate using a single digit and power of 10  </em></u>

23,898,497                      2 × 10⁷          

0.000136                          1 × 10⁻⁴

26,857                              3 × 10⁴

0.0302                             3 × 10⁻²

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Find the rational zeros of the polynomial function, f(x)= 4x^3-8x^2-19x-7
Dima020 [189]

Answer:

The rational zero of the polynomial are \pm \frac{7}{4}, \pm \frac{1}{4},\pm \frac{7}{2},\pm \frac{1}{2},\pm 7,\pm 1  .  

Step-by-step explanation:

Given polynomial as :

f(x) = 4 x³ - 8 x² - 19 x - 7

Now the ration zero can be find as

\dfrac{\textrm factor of P}{\textrm factor Q} ,

where P is the constant term

And Q is the coefficient of the highest polynomial

So, From given polynomial ,  P = -7 , Q = 4

Now , \dfrac{\textrm factor of \pm P}{\textrm factor of \pm Q}

I.e  \dfrac{\textrm factor of \pm P}{\textrm factor of \pm Q} = \frac{\pm 7 , \pm 1}{\pm 4 ,\pm 2,\pm 1 }

Or, The rational zero are \pm \frac{7}{4}, \pm \frac{1}{4},\pm \frac{7}{2},\pm \frac{1}{2},\pm 7,\pm 1

Hence The rational zero of the polynomial are \pm \frac{7}{4}, \pm \frac{1}{4},\pm \frac{7}{2},\pm \frac{1}{2},\pm 7,\pm 1  .  Answer

7 0
3 years ago
PLEASE HELP ASAP. IM TIMED​
ICE Princess25 [194]

It will be a parallelogram.

8 0
3 years ago
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In the first quadrant you start at (6,5)and move 3 unites left
VMariaS [17]

Answer:

<em>(3,5)</em>

I hope this helps!!



7 0
3 years ago
Cark earned grades of 62, 78, 59, and 89 on four tests.<br><br><br>what is the mean of his grades​
serious [3.7K]

Answer:

72

Step-by-step explanation:

mean=average. to get average, you add up the numbers and divide by how many numbers. they add upp to 288 and since theres 4 test grades, divide by 4 to get 72.

4 0
3 years ago
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Solving Exponential and Logarithmic Equations In Exercise, solve for x.<br> In 2x - In(3x - 1) = 0
LenKa [72]

Answer:

\frac{-1}{3x^2-x}

Step-by-step explanation:

  1. If f(x) is in th form of f(x)=g(x)-h(x) then f'(x)=g'(x) - h'(x)
  2. When f(x)=z(g(x)) then f'(x)= z'(g(x))g'(x) (called as chain rule)

<u>using these information</u>:

g(x)=ln2x then g'(x)=\frac{(2x)'}{2x} =\frac{2}{2x}=\frac{1}{x}

h(x)=In(3x - 1) then h'(x)=\frac{(3x-1)'}{3x-1} =\frac{3}{3x-1}f'(x)=g'(x) - h'(x) =[tex]\frac{1}{x} - \frac{3}{3x-1} =\frac{-1}{3x^2-x}

7 0
4 years ago
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