Ask question

Ask question

All categories

3 years ago

14

George collects 25 baseball cards each month. How many cards will he have at the end of one year? Complete the equation to help

you solve the problem. 25 × = n

2 answers:

s344n2d4d5 [400]3 years ago

7 0

Answer:300

Step-by-step explanation:

25 times 12

kaheart [24]3 years ago

4 0

25(cards per month) x12(months in one year) =300 cards at the end of one whole year

You might be interested in

for the function y = 15 - 6x, suppose the domain is only values of x from 10 to 20. What is the Range of the function?

emmainna [20.7K]

Y=-6(10)+15
y=-60+15
y=-45

y=-120+15
y=-105

range equals -105 to 45

5 0

4 years ago

Please help ill mark brainliest ✅✅✅✅

shepuryov [24]

Answer:

i think y=3/4x-4.2

Step-by-step explanation:

4 0

3 years ago

Please HELP. Picture above

Dmitrij [34]

Answer:

1. 1/2

2. 3/10

3. 11/20

4. 3/4

5. 4/5

6. 19/25

7. 6/25

8. 17/25

9. 11/25

10. 85%

11. 90%

12. 10%

13. 95%

14. 72%

15. 21%

Your welcome :D A brainliest, a heart, and a 5 star rating would be much appreciated. Thank You!

7 0

3 years ago

Given a function I and a subset A of its domain, let I(A) represent the range of lover the set A; that is, I(A) = {I(x) : x E A}

Ede4ka [16]

Step-by-step explanation:

(a)

Using the definition given from the problem

$f(A) = \{x^2 \, : \, x \in [0,2]\} = [0,4]\\f(B) = \{x^2 \, : \, x \in [1,4]\} = [1,16]\\f(A) \cap f(B) = [1,4] = f(A \cap B)\\$

Therefore it is true for intersection. Now for union, we have that

$A \cup B = [0,4]\\f(A\cup B ) = [0,16]\\f(A) = [0,4]\\f(B)= [1,16]\\f(A) \cup f(B) = [0,16]$

Therefore, for this case, it would be true that $f(A\cup B) = f(A)\cup f(B)$ .

(b)

1 is not a set.

(c)

To begin with

$A\cap B \subset A,B$

Therefore

$g(A\cap B) \subset g(A) \cap g(B)$

Now, given an element of $g(A) \cap g(B)$ it will belong to both sets, therefore it also belongs to $g(A\cap B)$ , and you would have that

$g(A)\cap g(B) \subset g(A \cap B)$ , therefore $g(A)\cap g(B) = g(A \cap B)$ .

(d)

To begin with $A,B \subset A \cup B$ , therefore

$g(A) \cup g(b) \subset g(A\cup B)$

7 0

4 years ago

Question is in photo.<br> Thanks

lana66690 [7]

Answer:

what do you mean for this question. What do you need help on?

7 0

3 years ago