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uysha [10]
3 years ago
14

George collects 25 baseball cards each month. How many cards will he have at the end of one year? Complete the equation to help

you solve the problem. 25 × = n
Mathematics
2 answers:
s344n2d4d5 [400]3 years ago
7 0

Answer:300

Step-by-step explanation:

25 times 12

kaheart [24]3 years ago
4 0
25(cards per month) x12(months in one year) =300 cards at the end of one whole year
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(-5)² =<br> -2³=<br> (-3) y el 5 chiquito arriba pero no me deja ponerlo =<br> (-2)⁴=<br> (-6)º=
natita [175]

Answer:

Hai

(-5)² = +25. i dont write - because 2 is a binary number.

-2³ = -8

(-3)(small5) = -243

(-2)⁴= +16

(-6)º= 1 ( because if any number's power is 0, then we can just write there 1.

good luck (:

3 0
3 years ago
Suppose that the sample standard deviation was s = 5.1. Compute a 98% confidence interval for μ, the mean time spent volunteerin
NISA [10]

Answer:

The 95% confidence interval would be given by (5.139;5.861)  

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

2) Confidence interval

Assuming that \bar X =5.5 and the ranfom sample n=1086.

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=1086-1=1085

Since the Confidence is 0.98 or 98%, the value of \alpha=0.02 and \alpha/2 =0.01, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.01,1085)".And we see that t_{\alpha/2}=2.33

Now we have everything in order to replace into formula (1):

5.5-2.33\frac{5.1}{\sqrt{1086}}=5.139    

5.5+2.333\frac{5.1}{\sqrt{1086}}=5.861

So on this case the 95% confidence interval would be given by (5.139;5.861)    We are 98% confident that the mean time spent volunteering for the population of parents of school-aged children is between these two values.

5 0
3 years ago
Change the following into mixed fraction 13/5​
Oduvanchick [21]

Answer:

2 3/5

Step-by-step explanation:

13/5​

5 goes into 13 2 time

2*5 =10

13-10 =3

There is 3 left over.  This goes over the denominator

2 3/5

7 0
3 years ago
Read 2 more answers
Marcia claims that the GCF for 2x^2, 4xy and 8xy^4 is 8x^2y^4. Is she correct? If not, what is the GCF?
posledela
The GCF is what they all have in common.
2x is the only thing they ALL share.
5 0
2 years ago
On the first part of a journey, Alan drove a distance of x km and his car used 6 litres of fuel.
irinina [24]

Answer:

\frac{600}{x+20}\text{ litres per 100 km}

Step-by-step explanation:

Given,

The number of litres consumed by car in (x+20) km = 6,

So, number of litres consumed by car in 1 km = \frac{6}{x+20},

Now, number of litres consumed by car in 100 km = 100 × litres consumed by car in 1 km

=100\times \frac{6}{x+20}

=\frac{600}{x+20}

Hence, the rate of fuel used by his car would be \frac{600}{x+20} litres per 100 km.

6 0
3 years ago
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