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Irina18 [472]
3 years ago
11

An excitatory signal is received at the dendrite of a pyramidal glutamate neuron. When the signal is released from the incoming

presynaptic dopaminergic axon, it is received as an inhibitory signal. However, this signal is not integrated properly with other incoming signals to that neuron. Which is the most likely site at which the error of integrating this signal with other incoming signals occurred
Biology
1 answer:
Molodets [167]3 years ago
8 0

Answer:

Soma

Explanation:

Soma is the site at which the error of integrating an excitatory signal with other incoming signals occurred. Another name for Soma is perikaryon.

This signal integrates chemical encoding of signal transduction from all other incoming signals and this signal is not integrated properly with other incoming signals to that neuron.

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Anastaziya [24]

Answer:

i think its D

Explanation:

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A food allergy is a reaction that occurs when the _____ system reacts to a harmless substance in food, such as a protein that do
Dahasolnce [82]

A food allergy is a reaction that occurs when the <u>body</u> system reacts to a harmless substance in food, such as a protein that does not undergo digestion

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Drag a "P" into the box if the statement is describing Photosynthesis. Drag an "R" into the box if the statement is describing R
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Answer:

1. P

2.P

3.R

4.R

.5.R

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8..P

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Explanation:

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5 0
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The statement "all objects in the universe attract each other," is an example of which of the following
Romashka [77]
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6 0
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A recessive allele causes phenylketonuria (PKU) when homozygote. If the frequency of the recessive allele is 0.05 in the populat
Radda [10]

Answer:

0.095

Explanation:

Phenylkentonuria is a disease caused by a recessive allele.

The frequency of the recessive allele + the frequency of the dominant allele equals 1.

The frequency of the recessive allele is q = 0.05

The frequency of the dominant allele then is p = 1  - q = 0.95

If people mate randomly, the frequency of the homozygous dominant genotype will be p², the frequency of the heterozygous genotype will be 2pq and the frequency of the homozygous recessive genotype will be q² .

2pq=2× 0.05 × 0.95

2pq=0.095

The heterozygote frequency in the population is 0.095

4 0
3 years ago
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