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chubhunter [2.5K]
3 years ago
12

What is the value of c?

Mathematics
2 answers:
yulyashka [42]3 years ago
3 0

Answer:

71

Step-by-step explanation:

kap26 [50]3 years ago
3 0
The answer is 71 degrees, considering that one is a right angle we know that it is 90 degrees and because all of the angles of a triangle added up is 180 we can do 180 - (90 + 42) = 48, 48 is a, then we know that angle B is on a supplementary angle with a so it would be 90 - a = b, plug it in it would be 90 - 48 = 42 then we would do the same thing to find angle c, 180 - (42 + 67) which equals 71
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Step-by-step explanation:

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3 years ago
PLEASE HELP ! Determine f of the quantity 2 plus h end quantity minus f of 2 all over h if f (x) = 5x − 6.
marissa [1.9K]

The value of the function is 5

<h3>What is function?</h3>

A function is defined as a relation between a set of inputs having one output each.

Given function:

f(x) = 5x − 6

Now f(2+h) - f(2) /h

= 5(2+h)-6 - 10+6/h

=10+ 5h -10/h

=5h/h

=5

Learn more about this concept here:

brainly.com/question/26102243

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6 0
2 years ago
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Marat540 [252]

Answer:

First option is the correct answer

Step-by-step explanation:

\angle HIL \: and \: \angle JIG\: are vertical angles.

5 0
4 years ago
A community had a population of 12,000 in 1985, which is increased to 20,000 in 2010. The saturation population is 80,000. Estim
ivann1987 [24]

Answer:

The right answer is :

(a) 23,200

(b) 24,514

(c) 22,926

Step-by-step explanation:

According to the question,

P_1 = 12000

P_2 = 20000

P_{sat}=80000

(a)

We know that the arithmetic growth formula will be:

⇒ P=Pi+K\times t...(1)

here,

⇒ K=\frac{P_2-P_1}{\Delta t}

        =\frac{20000-12000}{25}

        =\frac{80000}{25}

        =320

On putting the values in equation (1), we get

⇒ P_{2020}=20000+320\times 10

             =23,200

(b)

The geometric growth formula will be:

⇒ P=ln(Pi)+K\times t

here,

⇒ K=\frac{lnP_2-lnP_1}{\Delta t}

         =\frac{ln(20000)-ln(12000)}{25}

By putting the values of general log, we get

hence,

⇒ P_f=ln(20000)+0.0204\times 10

         =10.107

P_{2020}=e^{10.107}

          =24,514

(c)

⇒ P_f=P_{sat}-(P_{sat}-P_i)e^{-K\times t}

or,

⇒ K=-\frac{1}{\Delta t}ln(\frac{P_{sat}-P_2}{P_{sat}-P_1} )

from here, we get

        =0.005

hence,

⇒ P_{2020}=80000-(80000-20000)e^{-0.005\times 10}

             =80000-(60000)e^{-0.005\times 10}

             =22,926

5 0
3 years ago
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