Ask question

Ask question

All categories

3 years ago

11

What is 32.043 in expanded form?

1 answer:

PtichkaEL [24]3 years ago

7 0

<span>You just have to break each number with its value.
30+2+.04+.003</span>

You might be interested in

Ice Cream Sales and Earnings Number of Bars Sold (x) Total Earnings (y)(dollars) 0 50 1 52 2 54 3 56 Which equation best shows t

solmaris [256]

Y = 2x + 50,

It's easier to look at the first set of numbers and then make a formula from there. so we need x to be zero and y to be 50, which is why the formula listed works.

6 0

3 years ago

F(x)=x^(2)+3x+4 is this quadratic, linear, or neither

goblinko [34]

Quadratic
you’re welcome

8 0

2 years ago

What is the measure of angle w°? Show all work.

Korolek [52]

It’s 100 I’m pretty sure

3 0

3 years ago

The Patterson family has 3 kids, 1 boy and 2 girls. Suppose that for each birth, the probability of a boy birth is 1/2, and the

elena-14-01-66 [18.8K]

Answer:

$Probability = \frac{1}{8}$

Step-by-step explanation:

Given

Represent Boys with B and Girls with G

$P(B) = \frac{1}{2}$

$P(G) = \frac{1}{2}$

Required

Find the probability or having 1 boy 2 girls

Since the order is not important, the probability is calculated as follows;

$Probability = P(B) * P(G) * P(G)$

Substitute $\frac{1}{2}$ for P(B) and P(G)

$Probability = \frac{1}{2} * \frac{1}{2} * \frac{1}{2}$

$Probability = \frac{1 * 1 * 1}{2 * 2 *2}$

$Probability = \frac{1}{8}$

<em>Hence, the fractional probability is </em> $\frac{1}{8}$ <em></em>

<em></em>

7 0

3 years ago

Point B has coordinates (4,1). The x-coordinate of point A is -4. The distance between point A and point B is 10 units. What a

klasskru [66]

Given:

Point B has coordinates (4,1).

The x-coordinate of point A is -4.

The distance between point A and point B is 10 units.

To find:

The possible coordinates of point A.

Solution:

Let the y-coordinate of point A be y. Then the two points are A(-4,y) and B(4,1).

Distance formula:

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

The distance between point A and point B is 10 units.

$\sqrt{(4-(-4))^2+(1-y)^2}=10$

Taking square on both sides, we get

$(8)^2+(1-y)^2=100$

$(1-y)^2=100-64$

$(1-y)^2=36$

Taking square root on both sides, we get

$(1-y)=\pm \sqrt{36}$

$-y=\pm 6-1$

$y=1\mp 6$

$y=1-6$ and $y=1+6$

$y=-5$ and $y=7$

Therefore, the possible coordinates of point A are either (-4,-5) or (-4,7).

7 0

3 years ago