Rule: Divide by 2, then add 6. 56, 100, 34, 23 A. 23, 34, 56, 100 B. 23, 56, 34, 100 C. 100, 34, 56, 23 D. 100, 56, 34, 23

2 answers:

3 0

For this problem, it is described that a set of number (x, y, z, ...) is calculated by a series of identical operation using the preceding number. In this problem if we let x as the first number, the second number y is, y = (x/2) + 6. Then the 3rd number z is equal to, z = (y/2) + 6, so on. Thus for this problem, the solution is <span>D: 100, 56, 34, 23 through trial and error.</span>

PolarNik [594]3 years ago

3 0

the solution is D because of the following elements if you divide by two and add 6 the solution would be correctly be D.

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Given p (a) = 0.45, p (b) = 0.30, p (a ∩<br> b.= 0.05. find p (a|b).

Mice21 [21]

Use the conditional probability formula, P(a|b) = P(a and b)/P(b)

7 0

3 years ago

Round 392 to the nearest ten

Bezzdna [24]

Nearest 10 is according to the last digit.
if the digit is >5, it +1 to the tenth digit. If it's <5, it will be reduced to 0.

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5 0

3 years ago

Read 2 more answers

You are trying to recreate flubber because you are obsessed with that movie and you thought it was the coolest. you take 70% sli

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