Question

Rule: Divide by 2, then add 6. 56, 100, 34, 23 A. 23, 34, 56, 100 B. 23, 56, 34, 100 C. 100, 34, 56, 23 D. 100, 56, 34, 23

Answer 1

For this problem, it is described that a set of number (x, y, z, ...) is calculated by a series of identical operation using the preceding number. In this problem if we let x as the first number, the second number y is, y = (x/2) + 6. Then the 3rd number z is equal to, z = (y/2) + 6, so on. Thus for this problem, the solution is D: 100, 56, 34, 23 through trial and error.

Answer 2

the solution is D because of the following elements if you divide by two and add 6 the solution would be correctly be D.