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Dimas [21]
3 years ago
9

Solve this simultaneous equation 4s-3t=4 3s-5t=14

Mathematics
1 answer:
antiseptic1488 [7]3 years ago
6 0
4s-3s=4 then, s=4 

5t-3t=14 then, 2t=14 after, t=7
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Hi may anyone plz help. I know that the Square gives more pizza but not how much more.
Rudik [331]
Area of square pizza = 15 *15 = 225 in²
area of circular pizza = πr² = 3.14 * 8² = 200.96 in²

how much more = 225 - 200.96 = 24.04 in²
8 0
3 years ago
Read 2 more answers
FIRST CORRECT ANSWER WILL GET BRAINLIEST!!!
Mars2501 [29]
Their are 6 equilateral triangles in a regular hexagon:
The area of one triangle = (x²√3)/4, then:
1st answer: The area of the hexagon base: is  6 TIMES the area of one equilateral triangle [or, needed for 2nd, question, TOT AREA:(6x²√3)/4] = (3x²√3)/2] unit²

2nd answer: :
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4 0
4 years ago
(Worth 20 points) Triangle RST is similar to RVW
goldenfox [79]

12 mm is the correct answer

8 0
3 years ago
Read 2 more answers
STRUCTURE A quality control inspector at a bolt factory examines random bolts that come off the assembly line. All bolts being m
ELEN [110]

From an absolute value inequality, we have that:

  • The minimum diameter is 6.46 mm.
  • The maximum diameter is 6.54 mm.

  • The absolute value measures the <u>distance of a point or a function to the origin</u>.
  • One example of inequality is:

|f(x)| \leq a

Which has solution:

-a \leq f(x) \leq a

In this problem:

  • Bolts with a diameter of 6.5 mm, with a tolerance of 0.04 mm, thus the <u>absolute value of the difference of the diameter D and 6.5 has to be of at most 0.04</u>, that is:

|D - 6.5| \leq 0.04

Applying the solution:

-0.04 \leq D - 6.5 \leq 0.04

-0.04 \leq D - 6.5

D - 6.5 \geq -0.04

D \geq 6.46

\leq D - 6.5 \leq 0.04

D \leq 6.54

  • The minimum diameter is 6.46 mm.
  • The maximum diameter is 6.54 mm.

A similar problem is given at brainly.com/question/24835634

5 0
3 years ago
Calculate the volume of the cylinder. Use button, not 3.14. Round answer to the tenth place.
Volgvan

Answer:

68.69 m^3

Step-by-step explanation:

Volume of cone = \frac{1}{3}\pi r^{2}h

= \frac{1}{3}\pi (2.9^{2})(7.8)

= \frac{1}{3}\pi (65.6)\\

= \frac{1}{3}(206)

= 68.69 m^3

7 0
3 years ago
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