Answer:
Option C is correct.
Step-by-step explanation:
y = x^2-x-3 eq(1)
y = -3x + 5 eq(2)
We can solve by substituting the value of y in eq(2) in the eq(1)
-3x+5 = x^2-x-3
x^2-x+3x-3-5=0
x^2+2x-8=0
Now factorizing the above equation
x^2+4x-2x-8=0
x(x+4)-2(x+4)=0
(x-2)(x+4)=0
(x-2)=0 and (x+4)=0
x=2 and x=-4
Now finding the value of y by placing value of x in the above eq(2)
put x =2
y = -3x + 5
y = -3(2) + 5
y = -6+5
y = -1
Now, put x = -4
y = -3x + 5
y = -3(-4) + 5
y = 12+5
y =17
so, when x=2, y =-1 and x=-4 y=17
(2,-1) and (-4,17) is the solution.
So, Option C is correct.
-2(x + 6) + 3 = -11x + 4(x + 4)
-2x - 12 + 3 = -11x + 4x + 16
-2x - 9 = -7x + 16
5x = 25
<em>x = 5</em>
Hope this helps! :)
These are all the right answers:
The median isn’t affected much by one outlier.
The median is the number in the middle of an ordered set of data.
To find the median of an even data set, find the average of the two middle numbers.
Hope this helped :)
The square root is <span>33.941125497
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Answer:
BC = 40º
BMC = 40º
Step-by-step explanation: Since the measure the major and minor arcs add up to 360º, just subtract 320 from 360 to find BC which is 40º. <BMC is also 40º because the measure of the arc is equal to its corresponding angle.