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3 years ago

A 100 A current circulates around a 2.00-mm-diameter superconducting ring.

Physics

1 answer:

igomit [66]3 years ago

8 0

Answer:

0.000314 Am²

6.049*10^-7 T

Explanation:

From the definitions of magnetic dipole moment, we can establish that

= , where

= the magnetic dipole moment in itself

= Current, 100 A

= Area, πr² (r = diameter divided by 2). Converting to m², we have 0.000001 m²

On solving, we have

= ,

= 100 * 3.14 * 0.000001

= 0.000314 Am²

= (0)/4 * 2 / ³, where

(0) = constant of permeability = 1.256*10^-6

z = 4.7 cm = 0.047 m

B = 1.256*10^-6 / 4*3.142 * [2 * 0.000314/0.047³]

B = 1*10^-7 * 0.000628/1.038*10^-4

B = 1*10^-7 * 6.049

B = 6.049*10^-7 T

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a sailboat sails 50 km to the north then 80 km in the direction 38 degrees west of south. what is the net displacement of the bo

True [87]

Answer:

35.489km

Explanation:

a diagram illustrating the question is attached

now, applying cosine rule to find the displacement c

cosine rule;

c²=a²+b²-2abCos ∅

c²=50²+80²-2(50)(80)Cos 38°

c²=2500 + 6400 - (8000×0.9951)

c²=8900-7640.589

c²=1259.411

c= $\sqrt{1259.411}$

c=35.49km

8 0

4 years ago

Read 2 more answers

What are difference between a pur substance a mixture?

MA_775_DIABLO [31]

Answer:

A pure substance has only one substance while a mixture has two or more substances

Explanation:

8 0

3 years ago

1. On which date does the Antarctic Circle have 24 hours of daylight? A. June 21

sattari [20]

The date in which the Antarctic Circle has 24 hours of daylight on December 21st every year. When energy is transferred to air the particles of air become more excited and move around faster.

5 0

4 years ago

Read 2 more answers

Two train 75 km apart approach each other on parallel tracks, each moving at

creativ13 [48]

Answer:

The correct solution is "37.5 km".

Explanation:

Given:

Distance between the trains,

d = 75 km

Speed of each train,

= 15 km/h

The relative speed will be:

= $15 + (-15)$

= $30 \ km/h$

The speed of the bird,

V = 15 km/h

Now,

The time taken to meet will be:

$t=\frac{Distance}{Relative \ speed}$

$=\frac{75}{30}$

$=2.5 \ h$

hence,

The distance travelled by the bird in 2.5 h will be:

⇒ $D = V t$

$=15\times 2.5$

$=37.5 \ km$

6 0

3 years ago

A virtual image is formed 17.0 cm from a concave mirror having a radius of curvature of 39.0 cm. (a) Find the position of the ob

Wittaler [7]

Explanation:

Image distance, v = -17 cm (-ve for virtual image)

Radius of curvature of concave mirror, R = 39 cm

Focal length, f = -19.5 cm (-ve for a concave mirror)

(a) Using mirror's formula as :

$\dfrac{1}{v}+\dfrac{1}{u}=\dfrac{1}{f}$

$\dfrac{1}{u}=\dfrac{1}{f}-\dfrac{1}{v}$

$\dfrac{1}{u}=\dfrac{1}{-19.5}-\dfrac{1}{(-17)}$

u = 132.6 cm

So, the object is placed 132.6 cm in front of the mirror.

(b) Magnification of the mirror, $m=\dfrac{-v}{u}$

$m=\dfrac{-17}{132.6}$

m = -0.128

Hence, this is the required solution.

7 0

4 years ago