Answer:
The tip of her shadow is moving at the speed of 9.66 ft/sec
Explanation:
The height of the street light = 19 feet
The height of the woman = 5.25 feet
Distance between the woman and the base of the pole, x = 35 ft
The speed of the woman towards the pole, dx/dt = 7ft/sec
The distance from the base of the streetlight to the tip of the woman's shadow = y
The distance from the woman to the tip of her shadow = y - x
The diagram illustrating this description is shown below
Using similar triangle:
Find the derivative of both sides with respect to time, t
The tip of her shadow is moving at the speed of 9.66 ft/sec
Answer is A. Iron cobalt nickel
According to Newton's 3rd law, there will be equal and opposite force on the astronaut which is -6048 N
<h3>
What does Newton's third law say ?</h3>
The law state that in every action, there will be equal and opposite reaction.
Given that a rocket takes off from Earth's surface, accelerating straight up at 69.2 m/s2. We are to calculate the normal force (in N) acting on an astronaut of mass 87.4 kg, including his space suit.
Let us first calculate the force involved in the acceleration of the rocket by using the formula
F = ma
Where mass m = 87.4 kg, acceleration a = 69.2 m/s2
Substitute the two parameters into the formula
F = 87.4 x 69.2
F = 6048.08 N
According to the Newton's 3rd law, there will be equal and opposite force on the astronaut.
Therefore, the normal force acting on the astronaut is -6048 N approximately
Learn more about forces here: brainly.com/question/12970081
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Answer:
g = 0.4 m/s²
Explanation:
Given the following data;
Height = 5 meters
Time = 5 seconds
To find the acceleration due to gravity (g) on the planet;
Mathematically, the maximum height of an object is given by the formula;
H = ½gt²
Where;
H is the height measured in meters.
g is the acceleration due to gravity.
t is time measured in seconds.
Substituting into the formula, we have;
5 = ½ * g * 5²
5 = 0.5 * g * 25
5 = 12.5 * g
g = 5/12.5
g = 0.4 m/s²
Well, you didn't ask a question, and 4 m/s is not an angular speed.
So all I can offer is a couple of observations:
1). The tension in the rope is
M V² / R = (1.5 kg) x (4 m/s)² / R
= (24 kg-m²/s²) / (distance of the ball from the pole).
2). Tetherball was the only thing I played at camp,
more than 60 years ago, and I loved it !
It was a tough game, because we had to skin
our own T.Rex and use his hide to make the ball
and his guts for the rope.
