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nadya68 [22]
3 years ago
13

A girl and boy pull in opposite directions on a stuffed animal. The girl exerts a force of 3.5 N. The mass of the stuffed animal

is 0.2 kg, and it is accelerating to the right 2.5 m/s2.
What is the force that the boy is exerting? N
Physics
2 answers:
WARRIOR [948]3 years ago
8 0

4 N is the CORRECT awnser

givi [52]3 years ago
5 0
I'm gonna have to assume the girl is on the right side and boy on left.
The net force is the sum of all forces on an object (includes negatives).
Let's say the force of the boy is variable <em>b</em>.  Use the formula F = ma.

<em>b </em>+ 3.5 = 0.2(2.5)

This is now simple algebra.  Solve to get that <em />the boty is exerting a force of -3N to the left.
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The vertical component of the force exerted by the hi.nge on the beam is 114.77 N.

<h3>Tension in the cable</h3>

Apply the principle of moment and calculate the tension in the cable;

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Anticlockwise torque = ¹/₂WL

TL sinθ  =  ¹/₂WL

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<h3>Vertical component of the force</h3>

T + F = W

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Using y = ut - 1/2gt² where y = height of bridge, u = initial speed of stone = 0 m/s, g = acceleration due to gravity = -9.8 m/s² (negative since it is directed downwards)and t = time it takes the stone to hit the water surface.

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