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nadya68 [22]
3 years ago
13

A girl and boy pull in opposite directions on a stuffed animal. The girl exerts a force of 3.5 N. The mass of the stuffed animal

is 0.2 kg, and it is accelerating to the right 2.5 m/s2.
What is the force that the boy is exerting? N
Physics
2 answers:
WARRIOR [948]3 years ago
8 0

4 N is the CORRECT awnser

givi [52]3 years ago
5 0
I'm gonna have to assume the girl is on the right side and boy on left.
The net force is the sum of all forces on an object (includes negatives).
Let's say the force of the boy is variable <em>b</em>.  Use the formula F = ma.

<em>b </em>+ 3.5 = 0.2(2.5)

This is now simple algebra.  Solve to get that <em />the boty is exerting a force of -3N to the left.
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The bird is held in level flight due to the force exerted on it by the air as the bird beats its wings. What is the maximum valu
Cerrena [4.2K]

Answer:

 maximumforce is F = mg

Explanation:

For this case we must use Newton's second law,

     Σ F = m a

bold indicate vectors, so we will write it in its components x and y

 X axis

       Fₓ = maₓ

 Axis y

      Fy - W = m aa_{y}

Now let's examine our case, with indicate that the bird is level, the force of the wings can have a measured angle with respect to the x axis, where the vertical component is responsible for the lift, let's use trigonometry to find the components

      Cos θ = Fₓ / F

      Fₓ = F cos θ

      sin θ = Fy / F

      Fy = F sin θ

Let's replace and calculate

      F sin θ -w = m a

 

As the bird indicates that leveling at the same height, so the vertical acceleration is zero (ay = 0)

       F sin θ = w = mg

The maximum value of this equation occurs when the sin=1, in this case

      F = mg

3 0
3 years ago
The electric field in a 3.0mm×3.0mm square aluminum wire is 1.0×10−2 V/m . What is the current in the wire?
Gekata [30.6K]
So here is my answer. Given that the electric field in <span>a 3.0mm×3.0mm square aluminum wire is 1.0×10−2 V/m, this is how we find the current in the wire.
</span><span>First, we take the distance as 3mm or 0.003m. Using the formula E=V/d, where d is distance, v voltage and E electric field strength, we make V the subject, being V=Ed or 2.2*10^-2*0.003=6.6*10^-5V
</span>Hope this answers your question.
4 0
3 years ago
If Joe rides his bike for 15 minutes at 20 km/hour south, how far has he ridden? (Give the answer in km) Watch the units!
Virty [35]

Answer:

Distance covered by Joe, d = 5 km

Explanation:

It is given that,

Speed of Joe, v = 20 km/hour

Time taken by Joe, t = 15 minutes = 0.25 h

We need to find the distance he is covering. It can be calculated using definition of speed as :

v=\dfrac{d}{t}

d=v\times t

d=20\times 0.25

d = 5 km

So, Joe covers a distance of 5 km. Hence, this is the required solution.

3 0
3 years ago
Can we use the traditional methods of measurement? Are they reliable? If not why?​
Reil [10]

Answer:

Traditional methods of measurement involve methods like measurement using the arm, foot or hand span of a particular person which can and does varies form person to person and hence can't be reliable while the standard methods have a fixed standard value which is universal and same for everybody and every place and ..

4 0
2 years ago
Two people with a combined mass of 127 kg hop into an old car with worn-out shock absorbers. This causes the springs to compress
Elena-2011 [213]

Answer:

Total load = 2999.126 kg

Explanation:

Let the spring constant of the shock absorber be k.

We know that the force applied on a spring is directly proportional to elongated length and the constant of proportionality is called spring constant.

Thus

Force, F = kx

where,

x = elongation = 9.1 cm 0.091 m

mass of the people, m = 127 kg

F = weight of the people = mg = 127 x 9.8 = 1244.6 N

substituting these values in the first equation,

1244.6 = k x 0.091

thus, k = 13,676.923 N/m

Now we know that the time period, T of an oscillating spring with a load of mass m is

T = 2\pi \sqrt{\frac{m}{k} }

\frac{m}{k} = \frac{T^{2} }{4\pi ^{2} }

thus,

m = k\frac{T^{2} }{4\pi ^{2}}

T = 1.66s

substituting these values in the equation,

m =13,676.923\frac{1.66^{2} }{4\pi ^{2}  }

m = 2999.126 kg

3 0
3 years ago
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