Electric current or electricity
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time = 3.00 / 1.75
<span>time = 1.714 </span>
<span>now </span>
<span>distance = (initial velocity + final velocity) / 2 * time/ 1 </span>
<span>Hence</span>
<span>3 = ( 1.75 + final velocity) / 2 * 1.714 </span>
<span>3.5 - 1.75 = final velocity </span>
<span>Therefore, the final velocity is 1.75 m /s</span>
Answer:
(a) K.E = 56000 J = 56 KJ, (b) d = 116.618 m
Explanation:
Given:
m = 70 Kg, Vi = 40.0 m/s, Vf= 0 m/s, μk = 0.70
Solution:
(a) K.E. =? J (due to motion of the runner the mechanical energy loss is in the form K.E.)
K.E. = 1/2 m v² = 0.5 ×70 kg × (40.0 m/s)²
K.E = 56000 J = 56 KJ
(b) distance d =? m
W= F × d
∴W = K. E = 56000 J and F= mg μk
K.E. = mg μk × d
so 56000 J = 70 kg × 9.8 m/s² × 0.70 × d
d = 116.618 m
Because gravity is constant
<span>the only force acting in free-fall is gravity which points downward at 9.8 m/s</span>
The time taken by the ballast bag to reach the ground is 2.18 s
The ballast bag at rest with respect to the balloon has the upward velocity (u) of 4.6 m/s , which is the velocity of the balloon. When it is dropped from the balloon, its motion is similar to an object thrown upwards with an initial velocity <em>u </em>and it falls under the acceleration due to gravity<em> g.</em>
Taking the upward direction as positive and the downward direction as negative, the following equation of motion may be used.
The bag makes a net displacement <em>s</em> of 13.4 m downwards, hence
Its initial velocity is
The acceleration due to gravity acts downwards and hence it is negative.
Use the values in the equation of motion and write an equation for t.
Solving the equation for t and taking only the positive value for t,
t=2.18 s