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Answer:
We can express the equation for any linear equation with slope -2 and point (x0,y0) as:
Step-by-step explanation:
Incomplete question:
There is no point to complete the equation.
As we have no point to complete the linear equation, we will solve for any given point (x0,y0) and a slope of m=-2.
The linear equation can be written generically as:
If a point, like (x0,y0) belongs to the linear equation, it satisfies its equation. Then:
Then, we can calculate b as:
We can express the equation for any linear equation with slope -2 and point (x0,y0) as:
Answer:
Step-by-step explanation:
The general equation of a circle can be expressed as (x-a)²+(y-b)² = r² where (a,b) is the centre of the circle and r is the radius.
To show that the equation x² + y² +6y + 2 = 0 represents a circle, we need to write it in the format above using the completing the square method.
Given x² + (y² +6y) + 2 = 0
First we need to complete the square of the square in parenthesis by adding the square of half of the coefficient of y i.e to the equation and adding the constant to the other side of the equation as well.
x² + (y² +6y) + 2 = 0
<em>Hence the equation represents a circle with centre C at (0, -3) and radius of √7</em>