Given, the ratio of blocks A, B, C,D are in the ratio 4:7:3:1
Let us consider the common ratio to be ‘x’.
So, toy blocks with alphabet A is 4x and
toy blocks with alphabet B is 7x and 
toy blocks with alphabet C is 3x and
toy blocks with alphabet D is x
Again, the number of ‘A’ blocks is 50 more than the number of ‘C’ blocks.
As no. of ‘A’ and ‘C’ blocks are 4x and 3x respectively.
So,
4x=50 + 3x 
x=50
Thus, the number of ‘B’ blocks is 7x = 7(50) = 350
350 is the required number.
        
                    
             
        
        
        
Answer:
18
Step-by-step explanation:
3/5 x 30
(3 times 30)divided by 5
= 18 children are going.
Hope this helps:-) 
 
        
             
        
        
        
Answer:
1st quartile is 136
The second quartile is also the median 142
The third quartile is 162
The interquartile range is the difference between the 3rd and first quartile or 26
Step-by-step explanation:
 
        
             
        
        
        
The answer is A if I am correct