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3 years ago

10

U=ak/b solve for this equation a

2 answers:

Lesechka [4]3 years ago

7 0

A=ub/k. the way you get this is by symplfying both sides of the equation then isolate the variable. hope this helped :)

coldgirl [10]3 years ago

5 0

U=ak/b solve for a you have to isolate a ...in order to do that you must multiply both sides by b

ub=ak then divide both sides by k to isolate a

ub
--- =a
k

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How do you find the next three terms in the geometric sequence 9, -3, 1, , ... ?

levacccp [35]

Each term is being divided by -3, so the next three terms would be:

-1/3, 1/9, -1/27

7 0

3 years ago

A lake polluted by bacteria is treated with an antibacterial chemical. Aftertdays, thenumber N of bacteria per milliliter of wat

jeyben [28]

Answer:

N(1)=50 is a minimum

N(15)=4391.7 is a maximum

Step-by-step explanation:

<u>Extrema values of functions </u>

If the first and second derivative of a function f exists, then f'(a)=0 will produce values for a called critical points. If a is a critical point and f''(a) is negative, then x=a is a local maximum, if f''(a) is positive, then x=a is a local minimum.

We are given a function (corrected)

$N(t) = 20(t^2-lnt^2)+ 30$

$N(t) = 20(t^2-2lnt)+ 30$

(a)

First, we take its derivative

$N'(t) = 20(2t-\frac{2}{t})$

Solve N'(t)=0

$20(2t-\frac{2}{t})=0$

Simplifying

$2t^2-2=0$

Solving for t

$t=1\ ,t=-1$

Only t=1 belongs to the valid interval $1\leqslant t\leqslant 15$

Taking the second derivative

$N''(t) = 20(2+\frac{2}{t^2})$

Which is always positive, so t=1 is a minimum

(b)

$N(1)=20(1^2-2ln1)+ 30$

N(1)=50 is a minimum

(c) Since no local maximum can be found, we test for the endpoints. t=1 was already determined as a minimum, we take t=15

(d)

$N(15)=20(15^2-2ln15)+ 30$

N(15)=4391.7 is a maximum

7 0

3 years ago

30 POINTS FOR SIMPLE QUESTION

Komok [63]

-4 = y + 3

y = -4x - 3

Solve for Y in the first equation:

-4 = y +3

Subtract 3 from both sides:

y = -7

Now using the addition method:

rewrite the second equation as 4x+y = -3

Multiply y = -7 by - 1 to get -y = 7

Now add the two together:

4x +y = -3

-y =7

4x = 4

Divide each side by 4:

x = 4/4 = 1

Then replace x in one of the equations to solve for y which is -7

X = 1, Y = -7

5 0

3 years ago

What would be the first step you do to solve the equation below?<br><br><br><br> -19 = 15 - 6x

Westkost [7]

Answer:

you would transfer 15 to the other side

Step-by-step explanation:

-19=15-6x

-34=6x

6 0

3 years ago

Read 2 more answers

Find the midpoint of the segment with the following endpoints. (7,−2) and (1,−10)

Zinaida [17]

Answer:

The answer is

<h2> $(4 \: , \: - 6)$ </h2>

Step-by-step explanation:

The midpoint M of two endpoints of a line segment can be found by using the formula

<h3> $M = ( \frac{x1 + x2}{2} , \: \frac{y1 + y2}{2} )$ </h3>

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(7,−2) and (1,−10)

The midpoint is

<h3> $M = ( \frac{7 + 1}{2} , \: \frac{ - 2 - 10}{2} ) \\ = ( \frac{8}{2} , \: - \frac{12}{2} )$ </h3>

We have the final answer as

<h3> $(4 \: , \: - 6)$ </h3>

Hope this helps you

3 0

3 years ago