9/7-8/6= Find the expresstions

Mathematics

2 answers:

Sergio039 [100]2 years ago

8 0

Answer:
8/7 divided by 9/7=8/9

ludmilkaskok [199]2 years ago

5 0

8/7 divided by 9/7=8/9

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A taxi service charges a flat fee of $1.25 and $0.75 per mile. if henri has $14.00, which of the following shows the number of m

andrey2020 [161]

Option m = 17

y = total cost of the service
m = number of miles run

y = 1.25 + 0.75 m

Equal the cost to the amount available by Henri

14 = 1.25 + 0.75m

Solve for m

m = (14 - 1.25)/0.75 = 12.75 / 0.75 = 17 miles.

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3 years ago

For the function f(x) = 2x +3, evaluate f(3).

AveGali [126]

Answer:

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3 years ago

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What is the coefficient of x2y3 in the expansion of (2x + y)5?

Zigmanuir [339]

Option C:

The coefficient of $x^{2} y^{3}$ is 40.

Solution:

Given expression:

$(2 x+y)^{5}$

Using binomial theorem:

$(a+b)^{n}=\sum_{i=0}^{n}\left(\begin{array}{l}n \\i\end{array}\right) a^{(n-i)} b^{i}$

Here $a=2 x, b=y$

Substitute in the binomial formula, we get

$(2x+y)^5=\sum_{i=0}^{5}\left(\begin{array}{l}5 \\i\end{array}\right)(2 x)^{(5-i)} y^{i}$

Now to expand the summation, substitute i = 0, 1, 2, 3, 4 and 5.

$$=\frac{5 !}{0 !(5-0) !}(2 x)^{5} y^{0}+\frac{5 !}{1 !(5-1) !}(2 x)^{4} y^{1}+\frac{5 !}{2 !(5-2) !}(2 x)^{3} y^{2}+\frac{5 !}{3 !(5-3) !}(2 x)^{2} y^{3}$