Answer:
The question is asking which numbers are larger with respect to one another. An easy way to do this is to convert to decimals, or just memorize it. 1/2=0.5, 3/4=0.75, 2/3=0.666666. So descending order (largest to smallest) 3/4, 2/3, 1/2.
Answer:
b............ .......... which one is a b c d
For this case we must indicate the graph of the following inequality:
y≥1−3x
It is observed that inequality includes equality, so the boundary line of the graph will not be dotted, so we discard options D and C.
We test option A, we substitute the point (0,0) in the inequality, if it is fulfilled then the graph corresponds to it.
We test option A, we substitute the point (0,0) in the inequality, if it is fulfilled then the graph corresponds to it.
It is not fulfilled
We test the last option B, we choose the point (3,1) that belongs to the graph:
1≥1−3(3)
\1≥1−9
1≥−8
it is fulfilled
Answer:
<h3>
9, 11, 13, 15</h3>
Step-by-step explanation:
{k - some integer}
2k+1 - the first odd integer (the least)
5(2k+1) - five times the least
5(2k+1)+3 -<u> three more than five times the least</u>
2k+1+2 = 2k+3 - the odd integer consecutive to 2k+1
2k+3+2 = 2k+5 - the next odd consecutive integer (third)
2k+5+2 = 2k+7 - the last odd consecutive integer (fourth)
2k+1+2k+3+2k+5+2k+7 - <u>the sum of four odd consecutive integers</u>
2k+1 + 2k+3 + 2k+5 + 2k+7 = 5(2k+1) + 3
8k + 16 = 10k + 5 + 3
- 10k -10k
-2k + 16 = 8
-16 - 16
-2k = -8
÷(-2) ÷(-2)
k = 4
2k+1 = 2•4+1 = 9
2k+3 = 2•4+3 = 11
2k+5 = 2•4+5 = 13
2k+7 = 2•4+7 = 15
Check: 9+11+13+15 = 48; 48-3 = 45; 45:5 = 9 = 2k+1
Answer:
Step-by-step explanation:
Add 25 to both sides:
Square root both sides:
(Since a negative number multiplied by itself gives positive, there are two answers.)
