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Naya [18.7K]
3 years ago
11

The circle with center C was used as a model for a swimming pool. The length of

BC%7D" id="TexFormula1" title="\overline{BC}" alt="\overline{BC}" align="absmiddle" class="latex-formula"> is 10 m. What is the area of the pool?

Mathematics
2 answers:
SpyIntel [72]3 years ago
8 0

Answer:

314.16

Step-by-step explanation:

Because we have the radius given to us by BC, we can simply input it into the formula to find the area of a circle, pi(r)^2.

After we insert the given radius, we have pi(10)^2.

We can simply input it into our calculator to find the answer.

Verizon [17]3 years ago
5 0
Okay okay so when solving for the area you have to use:
A= πr ²
(pi r squared)
A=10x10
A=100π
A ≈314.2
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Laura left Dunkin Donuts at 1 PM traveling 30 mph. Two hours later her friend Jen left the same Dunkin Donuts and started after
Wewaii [24]

Answer:

It took Jen 4 hours to catch up with Laura

Step-by-step explanation:

Gaining speed 45-30= 15 mph

Laura's head start 30×2=60 miles

Time for Jen to catch up 60÷15= 4 hours

In other words

30(t+2)= 45t

30t+60= 45t

60=45t-30t

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t=4 hours

5 0
3 years ago
3x = 12 isolates the variable on one side?
lorasvet [3.4K]
First, Divide by 3 on both sides.
So 3x=12 will turn to 3x/3=12/3
Which isolates the variable x and the answer: x= 4
3 0
3 years ago
A student used the graph below to identify the minimum/maximum. The student said the graph had a maximum of 1. Explain the stude
11Alexandr11 [23.1K]

Answer: Answer is in the step.

Step-by-step explanation:

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7 0
3 years ago
What’s the answer to 5 1/2 x ? = 10
myrzilka [38]
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3 0
4 years ago
Surface Area of Cylinder=2πrh+2πr2
Alex

  • Find the surface area when r is 8 inches and h is 8 inches.

\qquad A. 160π in²

\qquad B. 154π in²

\qquad C. 288π in²

\qquad D. 256π in² ☑

We are given –

\qquad ⇢Radius of cylinder , r = 8 inches

\qquad⇢ Height of cylinder, h = 8 inches.

We are asked to find surface area of the given cylinder.

Formula to find the surface cylinder given by –

\bf \star \pink{ Surface\: Area_{(Cylinder)} = 2\pi rh +2\pi r^2 }

Now, Substitute given values –

\sf  \twoheadrightarrow  Surface\: Area_{(Cylinder)} = 2\pi rh +2\pi r^2

\sf  \twoheadrightarrow Surface\: Area_{(Cylinder)}  = 2 \pi \times 8 \times 8 + 2\pi \times 8^2

\sf  \twoheadrightarrow Surface\: Area_{(Cylinder)} = 2 \pi \times 8^2 + 2\pi \times 8^2

\sf  \twoheadrightarrow Surface\: Area_{(Cylinder)} = 2\pi \times 64 +2\pi \times 64

\sf  \twoheadrightarrow Surface\: Area_{(Cylinder)}  =128 \pi + 128\pi

\purple{\bf  \twoheadrightarrow Surface\: Area_{(Cylinder)}  = 256\pi \: in^2 }

  • Henceforth,Option D is the correct answer.

8 0
2 years ago
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