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Naya [18.7K]
3 years ago
11

The circle with center C was used as a model for a swimming pool. The length of

BC%7D" id="TexFormula1" title="\overline{BC}" alt="\overline{BC}" align="absmiddle" class="latex-formula"> is 10 m. What is the area of the pool?

Mathematics
2 answers:
SpyIntel [72]3 years ago
8 0

Answer:

314.16

Step-by-step explanation:

Because we have the radius given to us by BC, we can simply input it into the formula to find the area of a circle, pi(r)^2.

After we insert the given radius, we have pi(10)^2.

We can simply input it into our calculator to find the answer.

Verizon [17]3 years ago
5 0
Okay okay so when solving for the area you have to use:
A= πr ²
(pi r squared)
A=10x10
A=100π
A ≈314.2
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B) 864 feet

Step-by-step explanation:

Here's my answer. I'm not too sure how to form the equation though. Hope this helps :)

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Two people share £350 in the ratio 1 : 6.<br><br><br>Calculate each share.
EleoNora [17]

Answer:

£50 and £300

Step-by-step explanation:

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6 0
3 years ago
The length of the hypotenuse of a right angled triangle exceeds the length of the base by 2cm and exceeds twice the length of th
insens350 [35]

Answer: a = 8;  b = 15;  c = 17

Step-by-step explanation:

c = b + 2  and c = 2a + 1

b = c − 2 and a =  \frac{c-1}{2}

​

c² = b² + a²  

c^{2} = (c-2)^{2} + \frac{c-1}{2}\\

c^{2}= \frac{4 (c-2)^{2}+(c - 1)^{2}  }{4}

4c^{2}={4 (c^{2} + 4 -4c)+c ^{2}  + 1-2c

4c^{2}={4 c^{2} + 16 -16c)+c ^{2}  + 1-2c

c^{2}-18c+17=0

c(c -17)-1(c-17)=0

​(c -1)(c-17)=0

c = 1 or c = 17

If c = 1 then b = 1 - 2 = -1, that's not possible

So x = 17

b = 17 - 2 = 15

a = \frac{17-1}{2}  = 8

Length sides of the triangle are 17 cm, 15 cm and 8 cm.

I saw some of this on a site but I want to make sure its correct so we're gonna apply the pythagorean theory and see if its correct.

a^{2} + b^{2} = c^{2} \\8^{2} + 15^{2} = 17^{2} \\64 + 225 = 289\\289 = 289\\

This shows that this is correct.

Hope this helped! Again, some of this was from a site, not from me.

3 0
3 years ago
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