I hope this helps you

2x^2-4x+7=0 a=2 b=-4 c= 7

disctirminant =b^2-4ac

disctirminant =(-4)^2-4.2.7

disctirminant = 16-56= -40

x=-b+square root of disctirminant ÷2a

x=4+2square root of (-10)/4

x=2+square root of (-10)/2

x'=4 -2 square root of (-10)/4

x'=2 -square root of (-10)/2

6 0

2 years ago

5c squared- d squared+3/2c - 4d...c= -1. d= -4

riadik2000 [5.3K]

For this case we have the following expression:

$5c ^ 2-d ^ 2 + \frac {3} {2} c-4d$

We must find the value of the expression when:

$c = -1\\d = -4$

Substituting we have:

$5 (-1) ^ 2 - (- 4) ^ 2 + \frac {3} {2} (- 1) -4 (-4) =\\5 (1) -16- \frac {3} {2} + 16 =\\5-16- \frac {3} {2} + 16 =\\-11- \frac {3} {2} + 16 =\\- \frac {25} {2} + 16 =\\\frac {-25 + 32} {2} =\\\frac {7} {2}$

Finally, the value of the expression is:

$\frac {7} {2}$

ANswer:

$\frac {7} {2}$

5 0

3 years ago