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3 years ago

The sum of three consecutive consecutive integers is 141 what is the smallest integer

2 answers:

5 0

Let x=the smallest integer, x+1=the second smallest, x+2=the greatest.
x+x+1+x+2=141
3x+3=141
3x=138
x=46
46 is the smallest integer

zvonat [6]3 years ago

5 0

Our three consecutive integers can be represented as

X → first integer

X + 1 → second integer

X + 2 → third integer

If the sum of our three consecutive integers is 141, our equation will read...

X + X + 1 + X + 2 = 141

Now, we can simplify on the left. Once we simplify, our equation will now read

3x + 3 = 141

-3 -3 ← subtract 3 on both sides

3x = 138 ← divide by 3 on both sides

<u>X = 46</u> ← smallest integer

Therefore, the smallest integer is 46.

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A college bookstore marks up the price that it pays the publisher for a book by 35 %. If the selling price of a book is $ 87.00

Dimas [21]

Answer:the amount that the bookstore pay the publisher for the book is $64.4

Step-by-step explanation:

Let x represent the amount that the bookstore pay the publisher for the book.

The college bookstore marks up the price that it pays the publisher for a book by 35%. This means that the value of the mark up would be

35/100 × x = 0.35 × x = 0.35x

Therefore, the amount that the bookstore is selling the book would be

x + 0.35x = 1.35x

If the selling price of a book is $ 87.00, then it means that

1.35x = 87

x = 87/1.35 = 64.4

7 0

3 years ago

What is y to the 5th power divided by y to the 8th power?

swat32

All you have to do is divided the other two numbers and than find out what y I and divide that than you will get it

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4 years ago

Read 2 more answers

(10

Anni [7]

Given:

The matrix multiplication

$\begin{bmatrix}4&5&6\\1&2&3\end{bmatrix}\begin{bmatrix}10\\20\\30\end{bmatrix}$

To find:

The order of resulting matrix.

Solution:

We know that, if order of first matrix is $m_1\times n_1$ and the order of second matrix is $m_2\times n_2$ , then the order of these two matrices is $m_1\times n_2$ .

We have,

$\begin{bmatrix}4&5&6\\1&2&3\end{bmatrix}\begin{bmatrix}10\\20\\30\end{bmatrix}$

Here, the order of first matrix is $2\times 3$ and the order of the second matrix is $3\times 1$ . So, the order of the second matrix is $2\times 1$ . It is also written are 2 by 1.