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atroni [7]
3 years ago
9

three men tooth part in a business. they put in 2000naira, 4000naira and 1500nairaas capital. the profit made was divided among

them in the same proportion as the amounts put in. if the profit was 300naira,how much did each man get
Mathematics
1 answer:
seraphim [82]3 years ago
8 0

As a middle school teacher my students struggle with this so I will be explaining to u this but I WILL NOT be telling you the answer...

Remark

The general formula for this is

Number of items she can buy = N

Cost Per item = C

Total amount of money = T

Givens

T = 8000

C = 200 naira, 300 naira, 600 naira

N = ???

Substitute and solve

a 200 naira

N = 8000 / 200

N = 40 She can buy 40 items at 200 naira apiece

b 300 naira

N = 8000/300

N = 26.7 Normally you would round up, but she does not have quite enough money to buy 27 items. So round down. Answer 26 items at 300 naira apiece.

She has  (answer) naira left over.

C 600 Naira

N = 8000/600

N = 13.3 Again, you round down. So she can buy 13 items and there is 0.3333 naira left over

Note: I'm not familiar with the currency, so I don't know how to properly express the small amount she has left over. But the whole number is correct.

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3 years ago
Please help me with this question!!!!!
amm1812

Answer:

B. H(x)=-.008(x-82)^{2}+83

Step-by-step explanation:

Well lets graph the following equation first,

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3 0
4 years ago
Write an equation for the proportional relationship shown in the table.
VladimirAG [237]

9514 1404 393

Answer:

  y = 38x

Step-by-step explanation:

The constant of proportionality (k) is the value of y when x=1. The table shows that to be 38. Then the equation is ...

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3 0
3 years ago
I toss an unfair coin 12 times. This coin is 65% likely to show up heads. Calculate the probability of the following.
mars1129 [50]

Answer:

a. 0.0368

b. 0.99992131

c. 0.2039

d. 0.0048

e. 0.6533

Step-by-step explanation:

Let the probability of obtaining a head be p = 65% = 13/20 = 0.65. The probability of not obtaining a head is q = 1 - p = 1 -13/20 = 7/20 = 0.35

Since this is a binomial probability, we use a binomial probability.

a. The probability of obtaining 11 heads is ¹²C₁₁p¹¹q¹ = 12 × (0.65)¹¹(0.35) = 0.0368

b. Probability of 2 or more heads P(x ≥ 2) is

P(x ≥ 2) = 1 - P(x ≤ 1)

Now P(x ≤ 1) = P(0) + P(1)

= ¹²C₀p⁰q¹² + ¹²C₁p¹q¹¹

= (0.65)⁰(0.35)¹² + 12(0.65)¹(0.35)¹¹

= 0.000003379 + 0.00007531

= 0.0007869

P(x ≥ 2) = 1 - P(x ≤ 1)

= 1 - 0.00007869

= 0.99992131

c. The probability of obtaining 7 heads is ¹²C₇p⁷q⁵ = 792(0.65)⁷(0.35)⁵ = 0.2039

d. The probability of obtaining 7 heads is ¹²C₉q⁹p³ = 220(0.65)³(0.35)⁹ = 0.0048

e. Probability of 8 heads or less P(x ≤ 8) = ¹²C₀p⁰q¹² + ¹²C₁p¹q¹¹ + ¹²C₂p²q¹⁰ + ¹²C₃p³q⁹ + ¹²C₄p⁴q⁸ + ¹²C₅p⁵q⁷ + ¹²C₆p⁶q⁶ + ¹²C₇p⁷q⁵ + ¹²C₈p⁸q⁴

= = ¹²C₀(0.65)⁰(0.35)¹² + ¹²C₁(0.65)¹(0.35)¹¹ + ¹²C₂(0.65)²(0.35)¹⁰ + ¹²C₃(0.65)³(0.35)⁹ + ¹²C₄(0.65)⁴(0.35)⁸ + ¹²C₅(0.65)⁵(0.35)⁷ + ¹²C₆(0.65)⁶(0.35)⁶ + ¹²C₇(0.65)⁷(0.35)⁵ + ¹²C₈(0.65)⁸(0.35)⁴

= 0.000003379 + 0.00007531 + 0.0007692 + 0.004762 + 0.01990 + 0.05912 + 0.1281 + 0.2039 + 0.2367

= 0.6533

3 0
3 years ago
4.
-Dominant- [34]

Answer:

All four

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SSS, SAS, ASA, and HL

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