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Jlenok [28]
3 years ago
10

In the diagram, HGF is a straight line. Given EF = 4 cm and HG = GF = 3 cm, find :

Mathematics
1 answer:
Alecsey [184]3 years ago
7 0
If HG and GF are both 3, then the whole length of the base is 6. The tan ratio is the side opposite the reference angle (length 4) over the side adjacent to the angle (length 6), which for us looks like this:
tan(x)= \frac{4}{6} = \frac{2}{3}=.6666667
Now use the inverse tan button (2nd-->tan) to get
tan^{-1} (.66667)=33.69
As far as the sin y goes, you have to use the Law of Sines because you are not working with a right triangle in that case.  I mean you are as far as having to find out what the hypotenuses are triangle EFH and triangle EFG.  The hypotenuse in triangle EFH is 7.211, and the hypotenuse in triangle EFG is 5. Using the Law of Sines to solve for y, you get this:
\frac{siny}{7.211} = \frac{sin33.69}{5}
Solving for y and using the inverse sin gives you that y = 53.12
If you are not familiar with setting up the Law of Sines, nothing I could tell you here would help. If you are familiar, then you get the idea of where the numbers came from and why they are set up that way. Hope that helps. That second part was quite hard.

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The sum of two numbers is 70 and their difference is 30. Find the two numbers
ikadub [295]

Answer:

Our two numbers are 50 and 20

Step-by-step explanation:

Sum means add together

Difference means subtract each other

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x - y = 30

subtract from each other

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divide both sides by 2

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our first number is 50

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subtract both sides by 50

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jenyasd209 [6]

Answer:

Ix = Iy = \frac{ρπR^{4} }{16}

Radius of gyration x = y =  \frac{R}{4}

Step-by-step explanation:

Given: A lamina with constant density ρ(x, y) = ρ occupies the given region x2 + y2 ≤ a2 in the first quadrant.

Mass of disk = ρπR2

Moment of inertia about its perpendicular axis is \frac{MR^{2} }{2}. Moment of inertia of quarter disk about its perpendicular is \frac{MR^{2} }{8}.

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For Radius of gyration K, equate MK2 = MR2/16, K= R/4.

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