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Jlenok [28]
3 years ago
10

In the diagram, HGF is a straight line. Given EF = 4 cm and HG = GF = 3 cm, find :

Mathematics
1 answer:
Alecsey [184]3 years ago
7 0
If HG and GF are both 3, then the whole length of the base is 6. The tan ratio is the side opposite the reference angle (length 4) over the side adjacent to the angle (length 6), which for us looks like this:
tan(x)= \frac{4}{6} = \frac{2}{3}=.6666667
Now use the inverse tan button (2nd-->tan) to get
tan^{-1} (.66667)=33.69
As far as the sin y goes, you have to use the Law of Sines because you are not working with a right triangle in that case.  I mean you are as far as having to find out what the hypotenuses are triangle EFH and triangle EFG.  The hypotenuse in triangle EFH is 7.211, and the hypotenuse in triangle EFG is 5. Using the Law of Sines to solve for y, you get this:
\frac{siny}{7.211} = \frac{sin33.69}{5}
Solving for y and using the inverse sin gives you that y = 53.12
If you are not familiar with setting up the Law of Sines, nothing I could tell you here would help. If you are familiar, then you get the idea of where the numbers came from and why they are set up that way. Hope that helps. That second part was quite hard.

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Answer:

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Step-by-step explanation:

Since the cost for border paper is given in terms of feet and the dimensions of the gym are given in meters, we want to convert them to the same unit. Let's choose to convert feet to meters since that would be only one conversion:

15\:\mathrm{ft}=4.572\:\mathrm{m}

Therefore, the cost of border paper is $6.99 pet 15 feet or $6.99 pet 4.572 meters.

Since the gym is rectangular, the gym's perimeter is equal to:

p=15+27+15+27,\\p=2(15)+2(27)=84\:\mathrm{m}

Therefore, the cost of the total border paper for the gym is equal to:

\text{cost}=\frac{84}{4.572}\cdot 6.99\approx \boxed{\$128.43}

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