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trasher [3.6K]
4 years ago
13

What is the term to term rule for the sequence 4,12,36,108,324

Mathematics
2 answers:
OLEGan [10]4 years ago
5 0
Seems to be a geometric sequence

each term is 3 times the previus

a_n=a_1(r)^{n-1}
a_n is the nth term
a_1 is the first term
r is the comon ratio
n=which term


so first term is 4 and the common ratio is 3 so

a_n=4(3)^{n-1}

so the formula is
a_n=4(3)^{n-1} or in other notation
f(n)=4(3)^{n-1}
katovenus [111]4 years ago
5 0
A(n) = a(n-1)*3

There is a common ratio of 3 among the terms.
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We would need a sample size of 560.

We first calculate the z-score associated. with this level of confidence:
Convert 95% to a decimal:  95% = 95/100 = 0.95
Subtract from 1:  1-0.95 = 0.05
Divide by 2:  0.05/2 = 0.025
Subtract from 1:  1-0.025 = 0.975

Using a z-table (http://www.z-table.com) we see that this is associated with a z-score of 1.96.

The margin of error, ME, is given by:
ME=z*\sqrt{\frac{\hat{p}(1-\hat{p})}{n}}

We want ME to be 4%; 4% = 4/100 = 0.04.  Substituting this into our equation, as well as our proportion and z-score,
0.04=1.96\sqrt{\frac{0.63(1-0.63)}{n}}
\\
\\\text{Dividing both sides by 1.96,}
\\
\\\frac{0.04}{1.96}=\sqrt{\frac{0.63(0.37)}{n}}
\\
\\\text{Squaring both sides,}
\\
\\(\frac{0.04}{1.96})^2=\frac{0.63(0.37)}{n}
\\
\\\text{Multiplying both sides by n,}
\\
\\n(\frac{0.04}{1.96})^2=0.63(0.37)
\\
\\n(\frac{0.04}{1.96})^2=0.2331
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\\\text{Isolating n,}
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\\n=\frac{0.2331}{(\frac{0.04}{1.96})^2}=559.67\approx560
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