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Kaylis [27]
3 years ago
10

I am not good at this subject please HELP!

Mathematics
1 answer:
OleMash [197]3 years ago
8 0

Answer:

1) 24

2) 20.8

3) 14.7

Step-by-step explanation:

1) use pythagorean theorem

a^2 + b^2 = c^2 (a and b are the bases, c is the hypotenuse)

a = ?, b = 10, c = 26

a^2 + 10^2 = 26^2 ... (substitute the given values)

a^2 + 100 = 676 ... (find the square of 10 and 26)

a^2 = 576  ... (subtract 100 from both sides)

a = 24  ... (square root both sides)

2) use pythagorean theorem

a^2 + b^2 = c^2 (a and b are the bases, c is the hypotenuse)

a = 12, b = b, c = 24

12^2 + b^2 = 24^2 ... (substitute the given values)

144 + b^2 = 576 ... (find the square of 12 and 24)

a^2 = 432 ... (subtract 144 from both sides)

a ≈ 20.8 ... (square root both sides)

3) use pythagorean theorem

a^2 + b^2 = c^2 (a and b are the bases, c is the hypotenuse)

a = x, b = 15, c = 21

x^2 + 15^2 = 21^2 ... (substitute the given values)

x^2 + 225 = 441 ... (find the square of 15 and 21)

x^2 = 216 ... (subtract 225 from both sides)

x ≈ 14.7 ... (square root both sides)

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___________________________________

\qquad \purple{\twoheadrightarrow\bf 8x -2 y =48}

\qquad \twoheadrightarrow\sf  8x - \underbrace{2 \times 4} =48

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