Line graphs can also be used to compare changes over the same period of time for more than one group. Pie charts are best to use when you are trying to compare parts of a whole. They do not show changes over time. Bar graphs are used to compare things between different groups or to track changes over time.
Answer:
1.) Write the formula, which assigns double x to double n raised to the double z power.
Answer: 2\times x → 2\times n^(2\times z<u>)</u>
2.) Write a formula, which will add 5 to the cube of double t times double n, and assign it to double x.
Answer: 5\plus 2\times t^3→2\times x
3.) Write a formula, which will assign double x to square root of the sum of the squares of the lengths of the two legs of a triangle. Declare double leg1, and double leg2, in order to find the hypotenuse. (Pythagorean Theorem)
Answer: 2\times x → \sqrt \{(l^2)_1 + (l^2)_2\}= hypotenuse
4.) Write a program that find the distance between two values on the number line by taking the absolute value of their difference. Assign the answer to double x. The two numbers have been declared as follows:
double num1, num2
Answer: length = \sqrt\{|num2 - num1\|} → 2\times x
Explanation:
Answer:
Print the manual in a loose leaf binder so even small changes can be replaced
Explanation:
Procedure manual is the document that contains the business policies and strategies. These strategies can be changed time to time in the interest of company.
As these policies or procedures changes, it is necessary to communicate with all employees. To communicate this updated information to all employees it is necessary to print all that pages, where the changes have been made to replace them in the current manual. If we print whole manual it may increase the cost of printing. To reduce printing cost and wastage of pages only print those particular pages that have been changed. This will help to communicate to the existing employees as well as to newly hired employees.
Answer:
// program in C++.
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// string array
string m[3];
// array to store rainfall
double rainfall[3];
// variables
double avg_rainfall,sum=0;
for(int i=0;i<3;i++)
{
cout<<"Enter name of month "<<i+1<<" :";
// read month name
cin>>m[i];
cout<<"Enter rainfall (inches) in month "<<i+1<<" :";
// read rainfall
cin>>rainfall[i];
// sum of rainfall
sum+=rainfall[i];
}
// Average rainfall
avg_rainfall=sum/3;
// print Average rainfall
cout<<"Average rainfall for "<<m[0]<<","<<m[1]<<","<<m[2]<<" is "<<avg_rainfall<<" inches."<<endl;
return 0;
}
Explanation:
Create string array "m" to store name of month and double array "rainfall" to store rainfall. Read name of 3 months and rainfall in that month.Find the sum of all the rainfall and the average rainfall.Print the average rainfall of 3 months.
Output:
Enter rainfall (inches) in month 2 :45
Enter name of month 3 :july
Enter rainfall (inches) in month 3 :43
Average rainfall for may,june,july is 42.6667 inches.
