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blondinia [14]
2 years ago
11

A school is having a canned food drive. Each class is challenged to collect 220 cans. If there are x classes in the school, whic

h equation could be used to find the total number of cans, y, the school will collect if each class meets the challenge?
A. y = 20x
B. y = 220x
C. y = 220/x
D. y = 220 + x​
Mathematics
2 answers:
Naya [18.7K]2 years ago
8 0
The answer would be B since 220 is for each class (x) which is multiplication
lara31 [8.8K]2 years ago
5 0

Answer:

B)

Step-by-step explanation:

no. of Classes = x

cans = 220

220×x = 220x

no.of classes × cans = total number of cans

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What is the solution of (8x-8)^3/2=64<br>Edit; the answer is x=3
Talja [164]

I guess since you have the correct answer there that you need to know how to get it. Start by rewriting that exponent as a radical. It would look like this: \sqrt{(8x-8)^3}=64. The first step is to undo that square root by squaring both sides. That will give you this: (8x-8)^3=4096. Next we have to undo that cubing by taking the cubed root of both sides, leaving us with this: 8x-8=16. We add 8 to both sides to get 8x = 24 and x = 3.

6 0
3 years ago
When doctors prescribe medicine, they must consider how the drug’s effectiveness declines as time passes. If each hour a drug is
Dima020 [189]

Answer:

<u>The total time for the initial dose of 500 mg to reach a level of 150 mg is approximately 11 hours and 27 minutes </u>

Step-by-step explanation:

Initial dose = 500 mg

Let's calculate the effectiveness of the drug hour by hour, this way:

After 1 hour: 90% of 500 = 450 mg

After 2 hours: 90% of 450 = 405 mg

After 3 hours: 90% of 405 = 364.5 mg

After 4 hours: 90% of 364.5 = 328.05 mg

After 5 hours: 90% of 328.05 = 295.25 mg

After 6 hours: 90% of 295.25 = 265.73 mg

After 7 hours: 90% of 265.73 = 239.16 mg

After 8 hours: 90% of 239.16 = 215.24 mg

After 9 hours: 90% of 215.24 = 193.72 mg

After 10 hours: 90% of 193.72 = 174.35 mg

After 11 hours: 90% of 174.35 = 156.92 mg

After 12 hours: 90% of 156.92 = 141.23 mg

Difference between 11 and 12 hours: 156.92 - 141.23 = 15.7 mg

Difference per minute between 11 and 12 hours: 15.7/60 = 0.262 mg

Time to reach a level of 150 mg in minutes after 11 hours = (156.92-150)/0.262

Time to reach a level of 150 mg in minutes after 11 hours = 26.4

<u>The total time for the initial dose of 500 mg to reach a level of 150 mg is approximately 11 hours and 27 minutes </u>

4 0
3 years ago
Find the first partial derivatives of the function f(x,y,z)=4xsin(y−z)
Amanda [17]

Answer:

f_x(x,y,z)=4\sin (y-z)

f_x(x,y,z)=4x\cos (y-z)

f_z(x,y,z)=-4x\cos (y-z)

Step-by-step explanation:

The given function is

f(x,y,z)=4x\sin (y-z)

We need to find first partial derivatives of the function.

Differentiate partially w.r.t. x and y, z are constants.

f_x(x,y,z)=4(1)\sin (y-z)

f_x(x,y,z)=4\sin (y-z)

Differentiate partially w.r.t. y and x, z are constants.

f_y(x,y,z)=4x\cos (y-z)\dfrac{\partial}{\partial y}(y-z)

f_y(x,y,z)=4x\cos (y-z)

Differentiate partially w.r.t. z and x, y are constants.

f_z(x,y,z)=4x\cos (y-z)\dfrac{\partial}{\partial z}(y-z)

f_z(x,y,z)=4x\cos (y-z)(-1)

f_z(x,y,z)=-4x\cos (y-z)

Therefore, the first partial derivatives of the function are f_x(x,y,z)=4\sin (y-z), f_x(x,y,z)=4x\cos (y-z)\text{ and }f_z(x,y,z)=-4x\cos (y-z).

4 0
3 years ago
Help me please that’s easy but....
grin007 [14]

Let's resolve the powers of 10 to make them comparable

47000

45000

5000

280000

125000

Now you can see the largest is 280000 and the smallest is 5000

Their difference is 280000 - 5000 = 275000

4 0
3 years ago
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