Answer:
sorry ima need to use your page
Step-by-step explanation:
The answer is 5/8 ( i think)
Answer:
Step-by-step explanation:
<u>Congruent Triangles</u>
The figure shows two triangles FCD and FED. One of their sides is the radius of the circle, they both form a 90° angle with the line CD and ED and they share the same segment FD.
Thus, both triangles are congruent and we have the length of a side (12 units), one common side (the hypotenuse) and one unknown leg that must be equal. Therefore
Solving
The required side FD is the hypotenuse of any of the triangles. The unknown leg can be calculated by
Or
Thus
Solving
Straight lines will always add up to 180 degrees, so the angle that is missing here is supplementary to the other angle(adds up with the other angle to get 180) so we take 79 away from 180 and get 101 degrees
If the circle has the same center as the diagonals of a square and the radius of the circle is smaller than 1/2 the diagonal of the square but larger than 1/2 the length of the side of a square, then there are 8 points of intersection -- 2 at each corner of the square.
If the radius of the circle is smaller than 1/2 the side length of the square and the center is as described above, there are no points of intersection.
If the circle is located outside the square it can have 1 tangent point or 2 intersection points depending on the location conditions of the circle in relation to the square.
