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skelet666 [1.2K]
2 years ago
14

Greatest to least of 2, -1, -2, 0, 1

Mathematics
2 answers:
sleet_krkn [62]2 years ago
5 0

Answer:

2,1,0,-1,-2

Step-by-step explanation:

Just find the highest number and start going down.

Wittaler [7]2 years ago
4 0

Answer:

2,1,0,-1,-2

Step-by-step explanation:

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Do lines that intersect have a solution ? & how many
Marina CMI [18]

Answer:

Step-by-step explanation:

yes the value of x and y of the intersection point is the solution.

8 0
3 years ago
How do you find p and q?
Alborosie

Answer:

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Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Find the midpoint of the line segment joining the points P1 and P2.
ludmilkaskok [199]

Formula for midpoint between two points is M(x,y)

x=(x1+x2)/2 and y=(y1+y2)/2

In our case (x1,y1)=(m,b) and (x2,y2)=(0,0)

x=(m+0)/2=m/2 and y=(b+0)/2=b/2     M(m/2,b/2)

Good luck!!!

7 0
3 years ago
Verify that -5, 1/2, and 3/4 are the zeroes of the cubic polynomial 4x^3+20x^2+2x-3. Also verify the relationship between the ze
Finger [1]

Solution:

we have been asked to verify that -5, 1/2, and 3/4 are the zeroes of the cubic polynomial 4x^3+20x^2+2x-3

To verify that whether the given values are zeros or not we will substitute the values in the given Polynomial, if it will returns zero, it mean that value is Zero of the polynomial. But if it return any thing other than zeros it mean that value is not the zero of the polynomial.

Let f(x)=4x^3+20x^2+2x-3\\\\\text{when x=-5}\\\\f(-5)=4(-5)^3+20(-5)^2+2(-5)-3=-13\\\\\text{when x=}\frac{1}{2}\\

f( \frac{1}{2} ) = 4 ( \frac{1}{2} )^3+20(\frac{1}{2})^2+2(\frac{1}{2})-3=\frac{7}{2}\\\\

\text{when x=}\frac{3}{4}\\\\

f( \frac{3}{4} ) = 4 ( \frac{3}{4} )^3+20(\frac{3}{4})^2+2(\frac{3}{4})-3=\frac{183}{16}\\

Hence -5, 1/2, and 3/4 are not the zeroes of the given Polynomial.

Since sum of roots=\frac{-b}{a}= \frac{-20}{4}=-5\\

But -5+\frac{1}{2}+\frac{3}{4}=  \frac{-15}{4}\neq-5

Hence we do not find any relation between the coefficients and zeros.

Anyway if the given values doesn't represents the zeros then those given values will not have any relation with the coefficients of the p[polynomial.

6 0
3 years ago
Can anyone help with this?
Mademuasel [1]

Answer:

error

Step-by-step explanation:

8 0
3 years ago
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