A) 1/6
B) 5/6
C) 1
D) 20
Explanation:
A) There is one 6 on a 6-sided die, out of 6 numbers.
B) There are 5 numbers that are not 6 on a 6 sided die, out of 6 numbers.
C) P( 6 or ~6) = P(6) + P(~6) = 1/6 + 5/6 = 6/6 = 1
D) 1/6(120) = 120/6 = 20
The Mixture B is the answer! Hope this helps
Answer:
A rational number is said to be closed if the subtracted values and the result obtained are rational. Hence, the equations which supports the condition are :
5.5 - 0.5 = 4
5√4 - √4 = 4√4
Step-by-step explanation:
A.)
√8 - √8 = 0 ; the added values aren't rational and the result, Zero is not rational either.
B.)
5√4 - √4 = 4√4
5(2) - 2 = 2(2)
10 - 2 = 4
All the values in the expression are rational ; hence, it supports the assertion.
C)
5.5 - 0.5 = 4 ; all the values in the expression are rational, hence, it supports the fact.
2√3 - √3 = √3 ; the values in the expression are not rational, hence, it does not meet the condition.
Therefore, only options B and C supports the assertion.
Let me add that I learned most of this from Brainly a user named fichoh :)
B hope it helps have a good day
Answer:
The minimum value of f(x) is 2
Step-by-step explanation:
- To find the minimum value of the function f(x), you should find the value of x which has the minimum value of y, so we will use the differentiation to find it
- Differentiate f(x) with respect to x and equate it by 0 to find x, then substitute the value of x in f(x) to find the minimum value of f(x)
∵ f(x) = 2x² - 4x + 4
→ Find f'(x)
∵ f'(x) = 2(2)
- 4(1)
+ 0
∴ f'(x) = 4x - 4
→ Equate f'(x) by 0
∵ f'(x) = 0
∴ 4x - 4 = 0
→ Add 4 to both sides
∵ 4x - 4 + 4 = 0 + 4
∴ 4x = 4
→ Divide both sides by 4
∴ x = 1
→ The minimum value is f(1)
∵ f(1) = 2(1)² - 4(1) + 4
∴ f(1) = 2 - 4 + 4
∴ f(1) = 2
∴ The minimum value of f(x) is 2
