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SOVA2 [1]
3 years ago
8

The volume of a cylinder is given by the formula V = (pi)r^2h, where r is the radius of the cylinder and h is the height. Suppos

e a cylindrical can has radius (x - 3) and height (2x + 7). Which expression represents the volume of the can?
Mathematics
2 answers:
Y_Kistochka [10]3 years ago
5 0

Answer: The expression that represents the volume of the can (cylinder) is:

V=pi (2x+7) (x-3)^2

V=pi (2x^3-5x^2-24x+63)


Solution:

V=pi r^2 h

Radius of the cylinder: r=(x-3)

Height of the cylinder: h=(2x+7)

Replacing "r" by "(x-3)" and "h" by "(2x+7)" in the formula above:

V= pi (x-3)^2 (2x+7)

V=pi (2x+7) (x-3)^2

V=pi (2x+7) (x^2-2x(3)+3^2)

V=pi (2x+7)(x^2-6x+9)

V=pi ( 2x(x^2)-2x(6x)+2x(9)+7(x^2)-7(6x)+7(9) )

V=pi (2x^3-12x^2+18x+7x^2-42x+63)

V=pi (2x^3-5x^2-24x+63)

Luda [366]3 years ago
3 0
Pi(x-3)^2 *(2x + 7)

= 2pi(x)^3 - 5pi(x)^2 - 24pi(x) + 63pi

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<u>Solution:</u>

Given that line is passing through point (-5, 2) and (3, r)

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Slope of a line passing through point \left(x_{1}, y_{1}\right) \text { and }\left(x_{2}, y_{2}\right)  is given by following formula:

\text { Slope } m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}  --- eqn 1

\text { In our case } x_{1}=-5, y_{1}=2, x_{2}=3, y_{2}=\mathrm{r} \text { and } m=-\frac{1}{2}

On substituting the given value in (1) we get

\begin{array}{l}{-\frac{1}{2}=\frac{r-2}{3-(-5)}} \\\\ {\text { Solving the above expression to get value of } r} \\\\ {=>-\frac{1}{2}=\frac{r-2}{3+5}} \\\\ {=>-8=\frac{r-2}{3+5}} \\\\ {=>-8=2(r-2)} \\\\ {=>-8=2 r-4} \\\\ {=>2 r=-8+4} \\\\ {=>2 r=-4} \\\\ {=>r=\frac{-4}{2}=-2}\end{array}

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A horizontal trough is 16 m long, and its end are isosceles trapezoids with an altitude of 4 m, a lower base of 4 m, and an uppe
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Answer:

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Step-by-step explanation:

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=Area of the Trapezoid X Height of the Trough (H)

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