Answer is: 15675 J.
m (H₂O) = 75g - mass.
ΔT (H₂O)<span> = 75</span>°C - 25°C = 50°C -<span> change in temperature.</span>
C (H₂O) = 4,18 J/g·°C - <span>specific heat of water.
</span>Q = m·C·<span>ΔT.
Q- heat (in Joules-J).
</span>Q = 75g · 50°C · 4,18 J/g·°C = 15675J = 15,675 kJ.
Heat transfer<span> is a discipline that study</span><span> exchange, generation, use and conversion of </span>thermal energy<span> (</span>heat<span>) between physical systems.</span>
Correct answer is 
.
Phosphoric acid is a polyprotic acid having 3 acidic hyrdogen therefore it will have 3 pka values.
The equations for the release of acidic hydrogen can be written as:
From the pka values we can judge the idea of pH as using Henderson-Hasselbalch Equation, we get the relation between pH and pka.
Using the following equation, relation of pH and pka is
![pH=pka+log\frac{[A^-]}{HA}](https://tex.z-dn.net/?f=pH%3Dpka%2Blog%5Cfrac%7B%5BA%5E-%5D%7D%7BHA%7D)
Using this equation, we can find that the equation having pka= 2. 14 is closest to the pH=3.2 so the ionic form in this equation will be dominant at the same pH.
Therefore at pH=3.2 the ionic form of 
is dominant.
Answer:
V₂ = 123.6 L
Explanation:
According to Boyle's law pressure and volume of a gas are inversely related if amount and temperature are kept constant. For the initial and final states the gas law is given as,
P₁ V₁ = P₂ V₂ ----- (1)
Data Given;
P₁ = 103 kPa
V₁ = 30 L
P₂ = 25 kPa
V₂ = ?
Solution:
Solving equation 1 for V₂,
V₂ = P₁ V₁ / P₂
Putting values,
V₂ = (103 kPa × 30 L) ÷ 25 kPa
V₂ = 123.6 L
Result:
As the pressure is decreased from 103 kPa to 25 kPa, therefore, volume has increased from 30 L to 123.6 L.
Answer:
less then 50
Explanation:
please tell me if i right
Answer:
YEssss :)
happy april fools day everyone
