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Trava [24]
4 years ago
15

Elements are organized into groups / families according to their physical and chemical properties. Identify the elements that's

belong to each family based on there number of valence electrons. Write the names and symbol for each element
Chemistry
1 answer:
Kryger [21]4 years ago
3 0

Answer:

1 valence - Alkali Metals: Li Lithium, Na Sodium, K Potassium

2 valence - Alkaline Earth Metals: Be Beryllium, Mg Magnesium, Ca Calcium

3 valence - Non-metals: B Boron, Al Aluminium

4 valence - Non-metals: C Carbon, Si Silicon

5 valence - Non-metals: N Nitrogen, P Phosphorus

6 valence - Non-metals: O Oxygen, S Sulfur, Se Selenium

7 valence - Halogens: F Fluorine, Cl Chlorine, Br Bromine

8 valence - Noble Gases: He Helium, Ne Neon, Ar Argon

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ololo11 [35]

Answer:

    Try a grams calculator, Its pretty to nd one :D

Explanation:

8 0
3 years ago
Antonyms, synonyms and homonyms for normal fault
kirill115 [55]
Synonym: common fault
Antonym: un-normal fault
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6 0
4 years ago
What are the physical properties of chlorine?<br>​
Sonbull [250]

Answer:

The Physical Properties of Chlorine are as follows:

Color: Greenish-yellow.

Phase: Gas.

Odor: Disagreeable, suffocating smell.

Density: About two and one-half times as dense as air.

Solubility: Is soluble in water. ...

Boiling Point: The boiling point of chlorine is –34.05°C.

Melting Point: The melting point is –101°C.

Explanation:

Please mark me as the brainliest answer and please follow me for more answers

7 0
3 years ago
What mass of co was used up in the reaction with an excess of oxygen gas if 24.7 g of carbon dioxide is formed
sleet_krkn [62]
Balance Chemical Equation of this reaction is,

                                      2 CO  +  O₂   →   2CO₂

Acc. to this reaction,

88 g (2 mole) of CO₂ was produced when  =  56 g (2 mole)of CO was reacted
So, 
24.7 g of CO₂ will be produced by reacting =  X g of CO

Solving for X,

                                    X  =  (56 g × 24.7 g) ÷ 88 g

                                    X  =  2.26 g ÷ 88 g

                                    X  =  0.0257 g of CO

Result:
           
0.0257 g of CO is required to be reacted with excess of O₂ to produce 24.7 g of CO₂.
3 0
3 years ago
Compound X has a molar mass of 316.25 g*mol^-1 and the following composition:
Leokris [45]

Answer:

Compound X has a molar mass of 316.25 g*mol^-1 and the following composition:

element & mass %

phosphorus & 39.18%

sulfur & 60.82%

Write the molecular formula of X.

Explanation:

The given molecule of phosphorus and sulfur has molar mass --- 316.25 g.

Empirical formula calculation:                      

element:              phosphorus                       sulfur

co9mposition:      39.185%                            60.82%

divide with

atomic mass:          39.185/31.0 g/mol           60.82/32.0g/mol

                              =1.26mol                           1.90mol

smallest mole ratio:   1.26mol/1.26mol =1      1.90mol/1.26 mol =1.50

multiply with 2:          2                                         3

Hence, the empirical formula is:

P2S3.

Mass of empirical formula is:

158.0g/mol

Given, molecule has molar mass --- 316.25 g/mol

Hence, the ratio is:

316.25g/mol/158.0 =2

Hence, the molecular formula of the compound is :

2 x (P2S3)

=P_4S_6

8 0
3 years ago
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