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3 years ago

C. Balance these fossil-fuel combustion reactions. (1 point)

Chemistry

1 answer:

storchak [24]3 years ago

5 0

The question is incomplete. The complete question is :

C. Balance these fossil-fuel combustion reactions. (1 point)

C8H18(g) + 12.5O2(g) → ____CO2(g) + 9H2O(g) + heat

CH4(g) + ____O2(g) → ____CO2(g) + ____H2O(g) + heat

C3H8(g) + ____O2(g) → ____CO2(g) + ____H2O(g) + heat

C6H6(g) + ____O2(g) → ____CO2(g) + ____H2O(g) + heat

Solution :

C8H18(g) + 12.5O2(g) → __8__CO2(g) + 9H2O(g) + heat

When 1 part of octane reacts with 12.5 parts of oxygen, it gives 8 parts of carbon dioxide and 9 parts of water along with liberation of energy.

CH4(g) + __2__O2(g) → __1__CO2(g) + __2__H2O(g) + heat

When 1 part of methane reacts with 2 parts of oxygen, it gives 1 part of carbon dioxide and 2 parts of water along with liberation of energy.

C3H8(g) + __5__O2(g) → __3__CO2(g) + __4__H2O(g) + heat

When 1 part of propane reacts with 5 parts of oxygen, it gives 3 part of carbon dioxide and 4 parts of water along with liberation of energy.

C6H6(g) + __1/2__O2(g) → __6__CO2(g) + __3__H2O(g) + heat

When 1 part of propane reacts with 1/2 parts of oxygen, it gives 6 part of carbon dioxide and 3 parts of water along with liberation of energy.

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The production of ammonia (NH3) under standard conditions at 25°C is represented by the following thermochemical equation. N2(g)

asambeis [7]

Answer:

44,901 kilo Joule heat is released when $1.663\times 10^4 g$ grams of ammonia is produced.

Explanation:

Moles of ammonia gas produced :

$\frac{1.663\times 10^4 g}{17 g/mol}=978.235 mol$

According to reaction, when 2 moles of ammonia are produced 9.18 kilo joules of energy is also released.

So, When 978.235 moles of ammonia gas is produced the energy released will be:

$\frac{-91.8 kJ}{2}\times 978.235 mol=-44,900.98 kJ\approx -44,901 kJ$

(negative sign indicates that energy is released as heat)

44,901 kilo Joule heat is released when $1.663\times 10^4 g$ grams of ammonia is produced.

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3 years ago

Record your evidence about the Moon's appearance

Vilka [71]

Answer:

A solar eclipse .

It is one that occurs when the moon gets between the Earth and the Sun and it casts its shadow over the Earth. A solar eclipse only happens during the phase of new moon when the moon is indirect blockage of sun rays from reaching the earth thus causing a full shadow of the moon to fall on the Earth’s surface.

2 A lunar eclipse can only occur when there is a full moon. An eclipse of the moon happens only at full moon and only when the moon passes through some portion of the Earth’s shadow. The shadow in made of a two cone-shaped components, one which is nested inside the other.

3. Earth blocks sunlight from reaching the moon's surface. There are three categories of lunar eclipse according to the blockage of the sun rays. In a penumbral lunar eclipse, the moon passes through Earth’s penumbral shadow. The partial lunar eclipse occurs when a portion of the moon passes through Earth’s umbral shadow. The total lunar eclipse happens when the entire moon passes through Earth’s umbral shadow.

4.When an object in space comes between the sun and earth. It is one that occurs when the moon gets between the Earth and the Sun and it casts its shadow over the Earth. A solar eclipse only happens during the phase of new moon when the moon is indirect blockage of sun rays from reaching the earth thus causing a full shadow of the moon to fall on the Earth’s surface.

5.A total lunar eclipse. In this type of lunar eclipse, the events are clearly visible and striking to view because the Moon surface appear red in color. During the occurrence of the lunar eclipse events, 35% of the entire eclipse is total eclipse.

6. Wide, dark areas and strange spots and ridges –Galileo described the surface of the moon as being uneven and rough. In addition to that, he described the surface as crowded with depressions and bulges. In his original sketches, the long shadows cast by craters were represented by dark sided of the moon sketch.

7. Waxing gibbous .During the cycle of the moon, it undergoes several phases; new moon-new crescent-first quarter-waxing gibbous-full moon-waning gibbous-last quarter-old crescent-new moon. The new moon phase cannot be seen because the part receiving sun rays in then pointed away from the earth. The rest of the phases are visible from the earth.

8. New moon .

During the cycle of the moon, it undergoes several phases; new moon-new crescent-first quarter-waxing gibbous-full moon-waning gibbous-last quarter-old crescent-new moon. The new moon phase cannot be seen because the part receiving sun rays in then pointed away from the earth. The rest of the phases are visible from the earth.

9. Because the Southern Hemisphere has more direct sunlight .During the winter months, the Northern Hemisphere is tilted away from the sun, thus it receive sunrays at an angle thus it experiences the cold weather. At this period, it is summer in the Southern Hemisphere.

Explanation:

4 0

3 years ago

Question 6

kompoz [17]

Considering the combined law equation, the new temperature is -244.56 °C or 28.44 K.

<h3>Boyle's law</h3>

Boyle's law states that the pressure of a gas in a closed container is inversely proportional to the volume of the container, when the temperature is constant: if the pressure increases, the volume decreases while if the pressure decreases, the volume increases.

Mathematically, this law states that the multiplication of pressure by volume is constant:

P×V=k

<h3>Charles's law</h3>

Charles's law states that the volume is directly proportional to the temperature of the gas: if the temperature increases, the volume of the gas increases while if the temperature of the gas decreases, the volume decreases.

Mathematically, Charles' law states that the ratio of volume to temperature is constant:

$\frac{V}{T} =k$

<h3>Gay-Lussac's law </h3>

Gay-Lussac's law states that the pressure of a gas is directly proportional to its temperature: increasing the temperature will increase the pressure, while decreasing the temperature will decrease the pressure.

Mathematically, Gay-Lussac's law states that the ratio of pressure to temperature is constant:

$\frac{P}{T} =k$

<h3>Combined law equation</h3>

Combined law equation is the combination of three gas laws called Boyle's, Charlie's and Gay-Lusac's law:

$\frac{PxV}{T} =k$

Considering an initial state 1 and a final state 2, it is fulfilled:

$\frac{P1xV1}{T1} =\frac{P2xV2}{T2}$

<h3>New temperature</h3>

In this case, you know:

P1= 1 atm= 760 mmHg
V1= 15 L
T1= -30 °C= 243 K (being 0 °C= 273 K)
P2= 58 mmHg
V2= 23 L
T2= ?

Replacing in the combined law equation:

$\frac{760 mmHgx15 L}{243 K} =\frac{58 mmHgx23 L}{T2}$

Solving:

$T2x\frac{760 mmHgx15 L}{243 K} =58 mmHgx23 L$

$T2 =\frac{58 mmHgx23 L}{\frac{760 mmHgx15 L}{243 K}}$

Finally, the new temperature is -244.56 °C or 28.44 K.

Learn more about combined law equation:

brainly.com/question/4147359

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2 years ago

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tigry1 [53]

Atmospheric pressure decreases because air is less dense at higher altitudes. Because the atmospheric pressure is lower, the vapour pressure of the liquid needs to be lower to reach boiling point.

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