Iron (iii) chloride is obtained by vapor condensation from the reaction between chlorine gas and iron fillings.
<h3>How can iron (iii) chloride be formed from iron fillings?</h3>
Iron (ii) chloride can be formed from iron fillings in the laboratory as follows:
- Iron fillings + Cl₂ → FeCl₃
Chlorine gas is introduced into a reaction vessel containing iron fillings and the iron (iii) chloride vapor formed is obtained by condensation.
In conclusion, iron (iii) chloride is formed by the the direct combination of iron fillings and chlorine gas.
Learn more about iron (iii) chloride at: brainly.com/question/14653649
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Negative because it'll have to gain an electron
Answer:
Oxygen is in excess.
Explanation:
The coefficients of the balanced equation create a mole ratio that shows the ratio of how many reactants are used up and products are created.
The mole ratio of Mg to O2 in this equation is 2:1, which means that for every two moles of Mg used, there will be 1 mole of O2 used.
If we have 3.00 moles of Mg, we will only need 1.5 moles of oxygen to completely burn the Mg. Therefore, when all 3.00 moles of Mg are used, there will still be some of the 2.20 moles of oxygen remaining.
Hey there!
Consider 100 g of solution:
Mass of NaCl = 3.50% of mass of seawater
( 3.50 / 100 ) * 100 => 3.50 g
Number of moles as shown below:
Molar mass NaCl = 58.44 g/mol
n = Mass / molar mass
n = 3.50 / 58.44 => 0.059 moles of NaCl
Mass of sweater:
Mass of solution - Mass of NaCl
100 - 3.50 = 96.5 g
96.5 g in Kg :
96.5 / 1000 => 0.0965 Kg
Therefore ,calculate molality by using the following formula:
molality = number of moles of solute / mass of solution
molality = 0.059 / 0.0965
molality = 0.61 m
Hope That helps!
and
ions are held together by strong coloumbic attractive force. Hence NaCl has highest boiling point'
and
are polar protic molecules. Hence they possess london dispersion force, dipole-dipole force and hydrogen bonding as intermolecular forces.