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4 years ago

ANSWER FAST MY DUDEZ! What is the value of x in the equation 1.8- 3.7x = 4.2x + 0.3

Mathematics

1 answer:

Inessa [10]4 years ago

8 0

1.8- 3.7x = 4.2x + 0.3

Move 4.2x to the other side

Sign changes from +4.2x to -4.2x

1.8-3.7x-4.2x= 4.2x-4.2x+0.3

1.8-3.7x-4.2x= 0.3

1.8-7.9x= 0.3

Move 1.8 to the other side

Sign changes from +1.8 to -1.8

1.8-1.8-7.9x= 0.3-1.8

-7.9x= 0.3-1.8

-7.9x= -1.5

divide both sides by -7.9

-7.9/-7.9x= -1.5/-7.9

x= 0.18987341

Answer: x= 0.18987341

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

The complete question is

Consider this right triangle. 21 29 20 Write the ratio equivalent to: Sin B - CscA- Cot B

The picture of the question in the attached figure

Part 1) Write the ratio equivalent to: Sin B

we know that

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substitute the values

$sin(B)=\frac{21}{29}$

Part 2) Write the ratio equivalent to: Csc A

we know that

In the right triangle ABC

$csc(A)=\frac{1}{sin(A)}$

$sin(A)=\frac{BC}{AB}$ -----> by SOH (opposite side divided by the hypotenuse)

substitute the values

$sin(A)=\frac{20}{29}$

therefore

$csc(A)=\frac{29}{20}$

Part 3) Write the ratio equivalent to: Cot A

we know that

In the right triangle ABC

$cot(A)=\frac{1}{tan(A)}$

$tan(A)=\frac{BC}{AC}$ -----> by TOA (opposite side divided by the adjacent side)

substitute the values

$tan(A)=\frac{20}{21}$

therefore

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