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Aneli [31]
3 years ago
14

7y - 5z =29 4x+10y - 5z= -3

Mathematics
1 answer:
ArbitrLikvidat [17]3 years ago
8 0

Answer: yes because

Step-by-step explanation:

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32 divided by a number c
Drupady [299]
32/C would be the answer-
3 0
3 years ago
Pls helpi need it with this quiz
Bad White [126]

Answer:

Step-by-step explanation:

1.

one dollar = $1

2 1/2 = 2.5

$1 / 2.5 = $0.40 or 40 cents

2.

$3.78 / 6 = $0.63 or 63 cents

3.

$1.56 / 20 = $0.078

4.

1 1/2 = 1.5

$1.58 / 1.5 = $1.053

5.

$3.90/5 = $0.79 or 79 cents

3 0
3 years ago
Help help help help plz
igor_vitrenko [27]
can’t see the whole question
5 0
3 years ago
Consider the function f(x)=9-x^2/x^2-4 For which intervals is f(x) positive? Check ALL that apply.
solong [7]

Answer:

a. f (x) < 0 for x ∈ (-∞ ,-3)

b. f (x) > 0 for x ∈ (-3,-2)

c. f (x) < 0 for x ∈ (-2,2)

d. f (x) > 0 for x ∈ (2,3)

e.f (x) < 0 for x ∈ (3,∞)

Step-by-step explanation:

Here, the given function is:f(x)=   \frac{9-x^2}{x^2-4}

Now, to check for the sign of f(x) at x = k, put the value of x from the given interval.

We get:

<u>a. (-infinity, -3) </u>

put k = -4 from the given interval

We get f(-4)=   \frac{9-(-4)^2}{(-4)^2-4}  = \frac{9-16}{16-4}  = \frac{-7}{12}

⇒ f (x) < 0 for x ∈ (-∞ ,-3)

b. (-3, -2)

put k = -2.5 from the given interval

We get f(-2.5)=   \frac{9-(-2.5)^2}{(-2.5)^2-4}  = \frac{9-6.25}{6.25-4}  = \frac{2.75}{2.25}  > 0

⇒ f (x) > 0 for x ∈ (-3,-2)

c. (-2, 2)

put k = 0 from the given interval

We get f(0)=   \frac{9-(0)^2}{(0)^2-4}  = \frac{9}{-4}  = -\frac{9}{4}  < 0

⇒ f (x) < 0 for x ∈ (-2,2)

d. (2, 3)

put k =2.5 from the given interval

We get f(2.5)=   \frac{9-(2.5)^2}{(2.5)^2-4}  = \frac{9-6.25}{6.25-4}  = \frac{2.75}{2.25}  > 0

⇒ f (x) > 0 for x ∈ (2,3)

e. (infinity, 3)

put k = 4 from the given interval

We get f(4)=   \frac{9-(4)^2}{(4)^2-4}  = \frac{9-16}{16-4}  = \frac{-7}{12}

⇒ f (x) < 0 for x ∈ (3,∞)

7 0
4 years ago
HELP ME AND ANSWER THIS IK ITS -1 BUT ITS AN MULTIPLE CHOICE!! please don't guess thank you :) and I'll mark you as Brainlest :D
ankoles [38]
1 and 0 would also work for this inequality!
7 0
3 years ago
Read 2 more answers
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