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Anna11 [10]
3 years ago
11

Chance knows the length of a football field (including end zones) is 120 yards. The width of the football field is 53.33 yards.

What is the area of the football field, rounded appropriately?
Mathematics
2 answers:
Ira Lisetskai [31]3 years ago
6 0
<span>6399.6 yds </span>approximately 
Sphinxa [80]3 years ago
6 0
The answer is 6,399.6 but if you round it up it would be 6,400.
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One more time!
CaHeK987 [17]
Since q(x) is inside p(x), find the x-value that results in q(x) = 1/4

\frac{1}{4} = 5 - x^2\ \Rightarrow\ x^2 = 5 - \frac{1}{4}\ \Rightarrow\ x^2 = \frac{19}{4}\ \Rightarrow \\&#10;x = \frac{\sqrt{19} }{2}

so we conclude that
q(\frac{\sqrt{19} }{2} ) = 1/4

therefore

p(1/4) = p\left( q\left(\frac{ \sqrt{19} }{2} \right)  \right)

plug x=\sqrt{19}/2 into p( q(x) ) to get answer

p(1/4) = p\left( q\left( \frac{ \sqrt{19} }{2} \right) \right)\ \Rightarrow\ \dfrac{4 - \left(  \frac{\sqrt{19} }{2}\right)^2 }{ \left(  \frac{\sqrt{19} }{2}\right)^3 } \Rightarrow \\ \\ \dfrac{4 - \frac{19}{4} }{ \frac{19\sqrt{19} }{8}} \Rightarrow \dfrac{8\left(4 - \frac{19}{4}\right) }{ 8 \cdot \frac{19\sqrt{19} }{8}} \Rightarrow \dfrac{32 - 38}{19\sqrt{19}} \Rightarrow \dfrac{-6}{19\sqrt{19}} \cdot \frac{\sqrt{19}}{\sqrt{19}}\Rightarrow

\dfrac{-6\sqrt{19} }{19 \cdot 19} \\ \\ \Rightarrow  -\dfrac{6\sqrt{19} }{361}

p(1/4) = -\dfrac{6\sqrt{19} }{361}
3 0
3 years ago
Help!!!!!?!!!!!!!?!!?!!!!
Andreas93 [3]

Answer:

yellow

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
The darnells are having a swimming pool installed. the pool has a radius of 14 feet and a height of 4 feet. what is the volume o
Drupady [299]

Answer: 2461.76 cubic feet

Step-by-step explanation:

V=\pi r^{2} h\\\\V=(\pi)(14^{2})(4)\\\\V\approx (3.14)(14^{2})(4)=\boxed{2461.76}

8 0
2 years ago
I need help with this question I dont no what to answer for the question
monitta

answer:

23 and 32 are not symmetrical primes because they are not prime numbers


4 0
3 years ago
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Type the correct answer in the box.<br><br><br> In this triangle cosA/cosB= blank
Elina [12.6K]

Answer:

1

Step-by-step explanation:

A triangle is a polygon with three sides and three angles. The types of triangles are scalene triangle, equilateral triangle, right angled triangle and obtuse triangle.  

Trigonometric functions are used to show the relationship between the angles of a triangles and the sides of the triangle. For a right angled triangle, the ratio of the sides can be gotten using trigonometric functions such as:

cosθ = adjacent/hypotenuse, sinθ = opposite/hypotenuse, tanθ = opposite/adjacent

Given the right angle triangle:

cos(A) = adjacent / hypotenuse = 3 / 4.24

cos(A) = 3 / 4.25

cos(B) = adjacent / hypotenuse = 3 / 4.24

cos(B) = 3 / 4.24

cos(A) / cos(B) = (3 / 4.24) ÷ (3 / 4.24) = 1

cos(A) / cos(B) = 1

3 0
3 years ago
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