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lord [1]
3 years ago
8

HELP PLEASEEEEEEEE ASAPP

Mathematics
2 answers:
seraphim [82]3 years ago
4 0

Answer:

A is correct

Step-by-step explanation:

saveliy_v [14]3 years ago
4 0

Answer: A

Step-by-step explanation:

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In the similar quadrilaterals below, what is the length of AB?
Lana71 [14]

Answer:

there’s nothing there

Step-by-step explanation:

7 0
3 years ago
In order to estimate the mean amount of time computer users spend on the internet each month, how many computer users must be su
prisoha [69]

Answer:

1568

Step-by-step explanation:

The computation of the minimum sample size is shown below:

Given that

Error E = 11

The population standard deviation \sigma =217

Confidence level 1-α = 95%

Now following formula should be used

n > (Zalpha ÷ 2 × sigma ÷ E)^2

As we know that

Zalpha ÷ 2= 1.96

Now the sample size is

n> (1.96 × 202  ÷ 10)^2

= 1568

6 0
3 years ago
Find the 10th term of an arithmetic sequence if the common difference is 32 and the first term is 2
zaharov [31]

Answer:

290

Step-by-step explanation:

If the first term is 2 and the common difference is 32, then the formula for a(n) is:

a(n) = 2 + 32(n-1).

Thus, the 10th term is a(10) = 2 + 32(10-1)  =  2 + 32(9) = 290

6 0
3 years ago
Find all real solutions to the equation (x² − 6x +3)(2x² − 4x − 7) = 0.
Jet001 [13]

Answer:

x = 3 + √6 ; x = 3 - √6 ; x = \frac{2+3\sqrt{2}}{2} ;  x = \frac{2-(3)\sqrt{2}}{2}

Step-by-step explanation:

Relation given in the question:

(x² − 6x +3)(2x² − 4x − 7) = 0

Now,

for the above relation to be true the  following condition must be followed:

Either  (x² − 6x +3) = 0 ............(1)

or

(2x² − 4x − 7) = 0 ..........(2)

now considering the equation (1)

(x² − 6x +3) = 0

the roots can be found out as:

x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}

for the equation ax² + bx + c = 0

thus,

the roots are

x = \frac{-(-6)\pm\sqrt{(-6)^2-4\times1\times(3)}}{2\times(1)}

or

x = \frac{6\pm\sqrt{36-12}}{2}

or

x = \frac{6+\sqrt{24}}{2} and, x = x = \frac{6-\sqrt{24}}{2}

or

x = \frac{6+2\sqrt{6}}{2} and, x = x = \frac{6-2\sqrt{6}}{2}

or

x = 3 + √6 and x = 3 - √6

similarly for (2x² − 4x − 7) = 0.

we have

the roots are

x = \frac{-(-4)\pm\sqrt{(-4)^2-4\times2\times(-7)}}{2\times(2)}

or

x = \frac{4\pm\sqrt{16+56}}{4}

or

x = \frac{4+\sqrt{72}}{4} and, x = x = \frac{4-\sqrt{72}}{4}

or

x = \frac{4+\sqrt{2^2\times3^2\times2}}{2} and, x = x = \frac{4-\sqrt{2^2\times3^2\times2}}{4}

or

x = \frac{4+(2\times3)\sqrt{2}}{2} and, x = x = \frac{4-(2\times3)\sqrt{2}}{4}

or

x = \frac{2+3\sqrt{2}}{2} and, x = \frac{2-(3)\sqrt{2}}{2}

Hence, the possible roots are

x = 3 + √6 ; x = 3 - √6 ; x = \frac{2+3\sqrt{2}}{2} ; x = \frac{2-(3)\sqrt{2}}{2}

7 0
3 years ago
Many poker games start with each player being dealt five cards, called the player's "hand". Remember, there are 52 cards in a st
jek_recluse [69]

Answer:

The number of different possible poker hands is found by counting the number of ways that 5 cards can be selected from 52 cards, where the order is not important. It is a combination, so we use c n r

Step-by-step explanation:

The possible number of the poker hands is probably . C 52 5= 52!/5!x47!= 2598960

5 0
3 years ago
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