Personally I'd solve this inequality for y first: y < x-3.
That immediately eliminates (6,2) and (2,6).
Starting from y < x-3 and letting 2 sub for x and -1 sub for y, is the following true or false?
-1 < 2 -3 NO. -1 < -1 is false. Was there a fourth answer choice?
F(x) = 3(x-4)^2-38 because finding the perfect square would get you f(x)+38=3(x^2-8x+16) and then finding the squareroot of that and moving the constant on the left back to the right would leave u with f(x)=3(x-4)^2-38
Answer:
n+7
Step-by-step explanation:
When we have any unknown quantity, we can call it mostly x,y,z
so, here
Let take an unknown number = n
then
we need to do here " sum of a number and 7 in algebraic form"
so, it becomes
n + 7 (Answer)
8-2 and then 3 divided by 6 which will give you 0.5 so x=0.5
